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astra-53 [7]
3 years ago
9

A subatomic particle that has a positive charge and that is located in the nucleus of an atom

Physics
2 answers:
azamat3 years ago
4 0

Answer:

protons have a positive charge

Explanation:

neutrons have no charge

electrons have negative charge

wolverine [178]3 years ago
3 0

Answer:

c

Explanation:

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The gravitational force between two objects (mass1 = 10kg, mass2 = 6kg) is measured when the objects are 12 centimeters apart. I
Yanka [14]
Since the new distance is 3 times the old distance,
the new force is (1/3²) = 1/9th of the old force.

That's kind-of Choice-D, but I really don't like the way choice-D is worded.
"9 times smaller" is really pretty meaningless.  
8 0
3 years ago
Monochromatic light is incident on (and perpendicular to) two slits separated by 0.200 mm, which causes an interference pattern
marusya05 [52]

Answer:

I = 0.636*Imax

Explanation:

(a) To find the fraction of the maximum intensity at a distance y from the central maximum you use the following formula:

I=I_{max}cos^2(\frac{\pi d}{\lambda L}y)   (1)

I: intensity of light

Imax: maximum intensity of light

d: separation between slits = 0.200mm = 0.200 *10^-3 m

L: distance from the screen = 613cm = 0.613 m

y: distance to the central peak of the interference pattern

λ: wavelength of light = 656.3 nm = 656.3 *10^-9 m

You replace the values of all variables in the equation (1):

I=I_{max}cos^2(\frac{\pi (0.200*10^{-3}m)}{(656.3*10^{-9}m)(0.613m)}0.600m)\\\\I=I_{max}cos^2(937.06)=0.636I_{max}

Hence, the fraction of the maximum intensity is I = 0.636*Imax

6 0
3 years ago
Light waves are:<br> O Transverse waves<br> O Longitudinal Waves
Olenka [21]

Answer:

They are Transverse Waves.

3 0
3 years ago
Read 2 more answers
5. What is the mass (m) of an object with a speed (v) of 10 m/s and a momentum
ZanzabumX [31]

Answer:

0.54kg

Explanation:

p=mv

m=p/v

m=5.4/10

=0.54kg

4 0
3 years ago
Which of the following means that an image is located behind a lens? A. +di B. -di C. -do D. +do
STatiana [176]
For a lens, the following sign convention is generally used:

- f (the focal length) is positive for a converging lens and negative for a diverging lens
- d_o (the distance of the object from the lens) is positive if the object is in front of the lens and negative if it is behind the lens
- d_i (distance of the image from the lens) is positive if the image is behind the lens (real image) and negative if the image is in front of the lens (virtual image)

Therefore, the correct option is 
<span>A. +di
</span>which mens that the image is real and located behind the lens.

4 0
3 years ago
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