1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
S_A_V [24]
3 years ago
11

The power lines are at a high potential relative to the ground, so there is an electric field between the power lines and the gr

ound. To maximize the potential difference between one end of the fluorescent tube and the other, how should the tube be held
Physics
1 answer:
Makovka662 [10]3 years ago
8 0

Answer:

The tube should be held vertically, perpendicular to the ground.

Explanation:

As the power lines  of ground are equal, so its electrical field is perpendicular to the ground and the equipotential surface is cylindrical. Therefore, if we put the position fluorescent tube parallel to the ground so the both ends of the tube lie on the same equipotential surface and the difference is zero when its  potential.

And the ends of the tube must be on separate equipotential surfaces to optimize potential. The surface near the power line has a greater potential value and the surface farther from the line has a lower potential value, so the tube must be placed perpendicular to the floor to maximize the potential difference.

You might be interested in
_____ is not a hormone.
Arlecino [84]

Answer:

So, the correct answer is 'Melatonin'.

Explanation:

thank me later

4 0
3 years ago
Using Ohms Law, calculate the current that would exist in a circuit having a voltage of 240V experiencing 110 Ohms of resistance
anygoal [31]

To find the Voltage, ( V ) [ V = I x R ] V (volts) = I (amps) x R (Ω)

To find the Current, ( I ) [ I = V ÷ R ] I (amps) = V (volts) ÷ R (Ω)

To find the Resistance, ( R ) [ R = V ÷ I ] R (Ω) = V (volts) ÷ I (amps)

To find the Power (P) [ P = V x I ] P (watts) = V (volts) x I (amps)

8 0
3 years ago
A particle of charge +2q is placed at the origin and particle of charge -q is placed on the x-axis at x = 2a. Where on the x-axi
zzz [600]

Answer:

r_{31}=\frac{2a\sqrt{2}}{1+\sqrt{2}}  

Explanation:

We know that the electric force equation is:

F=k\frac{q_{1}*q_{2}}{r^{2}}

  • k is the electric constant 9*10^{9} Nm^{2}/C^{2}
  • r is the distance between the particles
  • q1 and q2 are the particle

Now, we have three particles, the first one at x=0, the second one at x=2a and the third in some place between these two particle.

1. Let's find the electric force between the first particle and the third particle.

F_{31}=k\frac{q_{3}*q_{1}}{r_{31}^{2}}

F_{31}=k\frac{q*2q}{r_{31}^{2}}

F_{31}=k\frac{2q^{2}}{r_{31}^{2}}

r(31) is the distance between 3 and 1

2. Now,  let's find the electric force between the third particle and the second particle.

F_{32}=k\frac{q_{3}*q_{2}}{x_{32}^{2}}

F_{32}=k\frac{q*(-q)}{r_{32}^{2}}

F_{32}=-k\frac{q^{2}}{r_{32}^{2}}

r(32) is the distance between 3 and 2.

Now, r_{31}+r_{32}=2a or r_{32}=2a-r_{31}

The net force must be zero so:

F_{31}+F_{32}=0[\tex][tex]k\frac{2q^{2}}{r_{31}^{2}}-k\frac{q^{2}}{r_{32}^{2}}=0[\tex]   [tex]kq^{2}(\frac{2}{r_{31}^{2}}-\frac{1}{r_{32}^{2}})=0[\tex] [tex]kq^{2}(\frac{2}{r_{31}^{2}}-\frac{1}{(2a-r_{31})^{2}})=0[\tex] It means that:[tex]\frac{2}{r_{31}^{2}}-\frac{1}{(2a-r_{31})^{2}}

We just need to solve it for r(31)

r_{31}^{2}=2(2a-r_{31})^{2}

r_{31}^{2}=2(2a-r_{31})^{2}

r_{31}=\frac{2a\sqrt{2}}{1+\sqrt{2}}  

Therefore the distance from the origin will be:

r_{31}=\frac{2a\sqrt{2}}{1+\sqrt{2}}  

I hope it helps you!        

                 

 

     

4 0
4 years ago
How can empty - shampoo bottles become useful?<br><br><br>​
Ganezh [65]
Crafting, reusing
Good luck!
4 0
3 years ago
Explain why a bolt of lightning is like the spark you might see when you touch a metal object and get a shock.
Cerrena [4.2K]

Answer:

Just like lightning, the spark you see is the discharge of static electricity that equalizes the charges.  When you touch a metal object and get a shock, electrons are travelling in between you and the object to equalize the charges of the two objects.  The light that is seen is the plasma created by electrons jumping between objects which heats the air surrounding them.  

6 0
3 years ago
Other questions:
  • A scientist claimed that fabric A is better able to resist fire than fabric B. Which option describes an experiment that will pr
    13·1 answer
  • A small 12.00 g plastic ball is suspended by a string in a uniform, horizontal electric field. If the ball is in equilibrium whe
    8·1 answer
  • Zirconium has an atomic number of 40. How many neutrons are there in an isotope of zirconium-92? A. 40 B. 52 C. 92 D. 132
    5·1 answer
  • A comet is in an elliptical orbit around the sun. its closest approach to the sun is a distance of 4.5 1010 m (inside the orbit
    11·1 answer
  • projectile motion of a particle of mass M with charge Q is projected with an initial speed V in a driection opposite to a unifor
    7·1 answer
  • How does distance between two objects affect their gravitational force
    9·1 answer
  • An automobile engine develops a torque of 280 NxM at 3800 rpm. What is the power in watts and horsepower?
    14·1 answer
  • It you balance a weight of 20 N at the 15 cm MARK and want to balance a weight of on the other side of the meter stick at 70 cm
    8·1 answer
  • What would be the formula if you<br> wanted to solve for the<br> acceleration?
    13·1 answer
  • What is neptune made out of?
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!