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S_A_V [24]
3 years ago
11

The power lines are at a high potential relative to the ground, so there is an electric field between the power lines and the gr

ound. To maximize the potential difference between one end of the fluorescent tube and the other, how should the tube be held
Physics
1 answer:
Makovka662 [10]3 years ago
8 0

Answer:

The tube should be held vertically, perpendicular to the ground.

Explanation:

As the power lines  of ground are equal, so its electrical field is perpendicular to the ground and the equipotential surface is cylindrical. Therefore, if we put the position fluorescent tube parallel to the ground so the both ends of the tube lie on the same equipotential surface and the difference is zero when its  potential.

And the ends of the tube must be on separate equipotential surfaces to optimize potential. The surface near the power line has a greater potential value and the surface farther from the line has a lower potential value, so the tube must be placed perpendicular to the floor to maximize the potential difference.

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What does the law of conservation of energy state?
VikaD [51]

The total amount of energy remains constant in an isolated system. It implies that energy can neither be created nor destroyed, but can be change from one form to another.

6 0
3 years ago
What is the wavelength of a 2.2 mhz ultrasound wave traveling through aluminum? assume that the speed of sound in aluminum is 51
Eva8 [605]
The frequency of a wave is equal to the linear speed divided the wavelength. so in equation form.
f = v / l
so the wavlength
l = v / f
where f is the frequency
v iss the linear speed
l is the wavelength

l = ( 5100 m/s ) / ( 2.2 Mhz ) ( 10^6 hz / 1 Mhz )
f = 0.0023 m
f = 2.3 mm
7 0
3 years ago
A baton twirler has a baton of length 0.36 m with masses of 0.48 kg at each end. Assume the rod itself is massless. The rod is f
AleksAgata [21]

Answer:

Part a)

When rotated about the mid point

\tau = 0.021Nm

Part b)

When rotated about its one end

\tau = 0.042 Nm

Explanation:

As we know that the angular acceleration of the rod is rate of change in angular speed

so we will have

\alpha = \frac{\Delta \omega}{\Delta t}

\alpha = \frac{2.4 - 0}{3.6}

\alpha = 0.67 rad/s^2

Part a)

When rotated about the mid point

I = 2mr^2

I = 2(0.48)(0.18)^2

I = 0.0311 kg m^2

now torque is given as

\tau = 0.0311 (0.67)

\tau = 0.021Nm

Part b)

When rotated about its one end

I = m(2r)^2

I = (0.48)(0.36)^2

I = 0.0622 kg m^2

now torque is given as

\tau = (0.0622)(0.67)

\tau = 0.042 Nm

3 0
3 years ago
Find a glass jar with a screw-top metal lid. Close the lid snugly and put the jar into the refrigerator. Leave it there for abou
DochEvi [55]

Answer:

The lid becomes tighter

It becomes tighter because metals have a lower heat capacity than glass meaning their temperature drops (or increases) much faster than glass for the same energy change. So in this example, the metal will contract faster than the glass causing it to be more tighter around the glass.

5 0
4 years ago
a 15kg child is riding a merry go round at 3rpm. what centripetal force must she exert if she is 8m from the center
Burka [1]

This is another application of Newton's second law of motion

         Force = (mass) x (acceleration).

The quantities are a little more complicated in circular motion than
they are in plain old straight-line motion.  In circular motion, the 'force'
is the centripetal force on the object, always pointing toward the center
of the circle.  And the 'acceleration' is the centripetal acceleration, also
pointing toward the center of the circle, and equal to

                        (speed)² / (radius).

The only thing we really need to find is the centripetal acceleration, and
then we'll have everything needed to plug into the formula and calculate
the centripetal force.

     Acceleration =    (speed)² / (radius).

     Speed = (distance) / (time) =

                   (3 circumferences) / (minute) =

                   (3 x 2pi x radius) / minute =

                    (6 pi x 8 meters) / (60 sec) =  0.8 pi m/s .

       Acceleration = (speed)² / (radius) =

                                 0.64 pi²  m²/s²  /  (8 meters) = 0.08 pi²  m/s²  =

                                                                               0.79 m/s² (rounded) .

       Force = (mass) x (acceleration) =

                       (15 kg) x (0.79 m/s²)  =  11.84 newtons
                                                    (about 2.66 pounds) .


I would not say that she "exerts this centripetal force".  The fact of
the matter is much simpler:  This is the force that something must
exert on her, pointing toward the center, in order to keep her revolving
around the center at that speed.  It could be the friction between her
shoes and the platform, if she's standing on the merry-go-round. 
It could be a rope tied between her ankle and something at the center
of the rotating platform.  It could be the safety belt on the horse that
she's riding.  Whatever it is, something has to constantly pull her toward
the center of the platform, with a force of 11.84 newtons, otherwise her
15kg body will not travel in that circular path.

8 0
3 years ago
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