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3 years ago

a bee flies 25m north of the hive, then 10m east, 5m west and 10m south. how far north and east of the hive is it now?

Physics

2 answers:

Vlad [161]3 years ago

8 0

Answer: 15m North and 5m East

Explanation: The bee first flies 25m northwards from the hive, and then from that point, flies 10m eastwards after which he flies westwards by 5m. This equates to it flying just 5m east (since 10m east — 5m west = 5m east).

Therefore the bee is just 5m east to the position of the hive.

From this point, it flies back down for 10m (southwards). This means of the 25m covered to the north of the hive, it has taken off 10m from it (25m north — 10m south = 15m north)

Therefore the bee is just 15m north of the location of the hive.

To pinpoint its location at this point in time, we would say the bee is located 5m to the East and 15m to the North of the hive.

krok68 [10]3 years ago

7 0

(25m north) + (10m south) = 15m north

(10m east) + (5m west) = 5m east

So the bee is now 15m north and 5m east of the hive.

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A conducting rod (length = 2.0 m) spins at a constant rate of 2.0 revolutions per second about an axis that is perpendicular to

vladimir2022 [97]

Answer:

0.050V

Explanation:

To solve this problem it is necessary to use the concepts related to the potential between two objects that have a magnetic field, this concept is represented in the equation.

$\int dV = \int_{0}^{l/2} Bv (dl)$

Where,

v= tangencial velocity

B = Magnetic Field

We know for definition that,

$v= l\omega$

Where,

L = length

$\omega =$ Angular velocity

We can replace this values in our first equation then,

$\int dV = \int_{0}^{l/2} B (l\omega) (dl)$

Integrating we have,

$V = \frac{1}{8} Bl^2 \omega$

Replacing the values,

$V= \frac{1}{8} (8*10^{-3})(12.56)(4)$

$V = 0.050V$

Therefore the potential difference between the center of the rod and the other rod is 0.050V

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3 years ago

Which of the following has the strongest magnetic field? Earth, the Sun, Jupiter, a pulsar

Ede4ka [16]

A pulsar has the strongest magnetic field

5 0

3 years ago

Read 2 more answers

A 30-m-long rocket train car is traveling from Los Angeles to New York at 0.5c when a light at the center of the car flashes. Wh

Novosadov [1.4K]

Given that,

Distance =30 m

speed = 0.5c

(A). We need to find the bell and siren simultaneous events for a passenger seated in the car

According to given data

The distance travelled by the light to reach either side of the rocket train car is same.

So, The two events are simultaneous and the bell and siren are the simultaneous events for a passenger seated in the car.

(B). We need to calculate time interval between the events

Using formula of time dilation

$\Delta t=\dfrac{\Delta t'}{\sqrt{1-\dfrac{v^2}{c^2}}}$ .....(I)

Where, $\delta t'$ = proper time

$\delta t$ = time interval between the events

The time interval between the events measured in a reference frame

The proper time in this case is

$\Delta t'=\Delta t_{1}-\dfrac{v\Delta x}{c^2}$

For the second interval,

Put the value of $\Delta t'$ in the equation (I)

$\Delta t_{2}=\dfrac{\Delta t_{1}-\dfrac{v\Delta x}{c^2}}{\sqrt{1-\dfrac{v^2}{c^2}}}$

Put the value in the equation

$\Delta t_{2} = \dfrac{0-\dfrac{0.5c\times30}{c^2}}{\sqrt{1-\dfrac{0.5^2c^2}{c^2}}}$

$\Delta t_{2}=\dfrac{-15}{3\times10^{8}\sqrt{1-0.25}}$

$\Delta t_{2}=-5.77\times10^{8}\ s$

Negative sign shows the siren rings before the bell ring.

Hence, (A). Yes, the bell and siren are simultaneous events.

(B). The siren sounds before the bell rings.

8 0

3 years ago

You prepare tea with 0.250 kg of water at 85.0 ºC and let it cool down to room temperature (20.0 ºC) before drinking it. Essenti

vladimir2022 [97]

Answer:

232 J/K

Explanation:

The amount of heat gained by the air = the amount of heat lost by the tea.

q_air = -q_tea

q = -mCΔT

q = -(0.250 kg) (4184 J/kg/ºC) (20.0ºC − 85.0ºC)

q = 68,000 J

The change in entropy is:

dS = dQ/T

Since the room temperature is constant (isothermal):

ΔS = ΔQ/T

Plug in values (remember to use absolute temperature):

ΔS = (68,000 J) / (293 K)

ΔS = 232 J/K

5 0

2 years ago

All of the following could be considered reconstruction except

mylen [45]

The first three choices: a, b and c can be considered reconstruction except the last one which is letter d. I'm not really certain what reconstruction is, but judging from the patterns of the first three choices, reconstruction could mean that an inference is made after a part of an event has proved that event to be true.

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3 years ago