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Studentka2010 [4]
3 years ago
8

Helppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

Mathematics
1 answer:
Alja [10]3 years ago
5 0

Answer:

1/2p+2

Step-by-step explanation:

1/2 distributed to p would be 1/2p. 1/2 distributed to 4 would be the same as 1/2 * 4/1. When you multiply straight across you get 4 in the numerator and 2 in the denominator (4/2). Next you just reduce the fraction, 4 divided by 2 is 2. So, the answer would be 1/2p+2. That answer would go into the 2 empty boxes. Hope thaat helps!!!

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Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 4 right angle0,−4 in the directions pa
Nikolay [14]

Answer:

F_p = < - \sqrt{3} , -3 >\\\\F_o = < \sqrt{3} , -1 >

Step-by-step explanation:

- A plane is oriented in a Cartesian coordinate system such that it makes an angle of ( π / 3 ) with the positive x - axis.

- A force ( F ) is directed along the y-axis as a vector < 0 , - 4 >

- We are to determine the the components of force ( F ) parallel and normal to the defined plane.

- We will denote two unit vectors: ( u_p ) parallel to plane and ( u_o ) orthogonal to the defined plane. We will define the two unit vectors in ( x - y ) plane as follows:

- The unit vector ( u_p ) parallel to the defined plane makes an angle of ( 30° ) with the positive y-axis and an angle of ( π / 3 = 60° ) with the x-axis. We will find the projection of the vector onto the x and y axes as follows:

                         u_o = < cos ( 60° ) , cos ( 30° ) >

                         u_o = < \frac{1}{2} ,  \frac{\sqrt{3} }{2} >

- Similarly, the unit vector ( u_o ) orthogonal to plane makes an angle of ( π / 3 ) with the positive x - axis and angle of ( π / 6 ) with the y-axis in negative direction. We will find the projection of the vector onto the x and y axes as follows:

                        u_p = < cos ( \frac{\pi }{6}  ) , - cos ( \frac{\pi }{3} ) >\\\\u_p = < \frac{\sqrt{3} }{2}  , -\frac{1}{2}  >\\

- To find the projection of force ( F ) along and normal to the plane we will apply the dot product formulation:

- The Force vector parallel to the plane ( F_p ) would be:

                          F_p = u_p(F . u_p)\\\\F_p = < \frac{1}{2} , \frac{\sqrt{3} }{2} > [  < 0 , - 4 > . < \frac{1}{2} , \frac{\sqrt{3} }{2} > ]\\\\F_p = < \frac{1}{2} , \frac{\sqrt{3} }{2} > [ -2\sqrt{3}  ]\\\\F_p = < -\sqrt{3}  , -3 >\\

- Similarly, to find the projection of force ( F_o ) normal to the plane we again employ the dot product formulation with normal unit vector (  u_o  ) as follows:

                         F_o = u_o ( F . u_o )\\\\F_o = < \frac{\sqrt{3} }{2} , - \frac{1}{2} > [ < 0 , - 4 > . < \frac{\sqrt{3} }{2} , - \frac{1}{2} > ] \\\\F_o = < \frac{\sqrt{3} }{2} , - \frac{1}{2} > [ 2 ] \\\\F_o = < \sqrt{3} , - 1 >

- To prove that the projected forces ( F_o ) and ( F_p ) are correct we will apply the vector summation of the two orthogonal vector which must equal to the original vector < 0 , - 4 >

                       F = F_o + F_p\\\\< 0 , - 4 > = < \sqrt{3}, -1 > + < -\sqrt{3}, -3 >  \\\\< 0 , - 4 > = < \sqrt{3} - \sqrt{3} , -1 - 3 > \\\\< 0 , - 4 > = < 0 , - 4 >  .. proven                    

8 0
4 years ago
Identify the geometric mean of 1/3 and 1/27.
Lesechka [4]

Answer:

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Step-by-step explanation:

To find the geometric mean of two numbers,  multiply them together, then take the square root

G.M = sqrt( 1/3 * 1/27)

        = sqrt(1/81)

       = 1/9

6 0
3 years ago
PLEASE HELP ME WITH THIS QUESTION ASAP!!!
Naily [24]
Distribution is the way I learned it.

6 0
2 years ago
julia is standing 2 feet away away from a lamppost. she casts a shadow of 5 feet and the light make a 20 degree angle relative t
NikAS [45]

Height of the lamp post is 2.5 ft.

<u>Step-by-step explanation:</u>

AB = lamp post

CD = Julia

CE = Shadow

AC = 2 ft , CE = 5 ft , ∠AEB = 20°

AE = AC+ CE = 2+ 5 = 7 ft

Considering ABE as a right triangle, we can write the tan ratio as,

tan ∠AEB = opp/adj = AB/AE

AB = AE × tan ∠AEB

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So, height of the lamp post is 2.5 ft.

<u></u>

3 0
4 years ago
Six years less than Tracy's age
horsena [70]
If tracey's age is x

then x-6 is the expression for six years less than tracy's age

is this what you need? 
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5 0
4 years ago
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