Answer:
ΔH=15000
J = 15KJ
Explanation:
In this exercise you have find the enthalpy of reaction this is the difference between enthalpy of reactans and products,
For the following equation
H2A(aq) + 2 BOH(aq) → B2A(aq) + 2 H2O(l)
We know that 0.20 moles of BOH reacted with excess amount of H2A solution and 1500. J
so,
(2mol/0,2mol)*1500J=15000J
for de reactions exothermics tha enthalpy is negative so:
ΔH=15000
J = 15KJ
Answer:
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Explanation:
Beacuse its bewdcbhidbcwejnc
Answer:
See the answer and explanation below, please.
Explanation:
The formulas and names of the compunds are:
Na3 P04 (Sodium Phosphate )-->The phosphate suffix corresponds to the highest number of phosphorus oxidation (+5)
Zn PO4 (Zinc Sulfate)-->The phosphate suffix corresponds to the highest number of phosphorus oxidation (+5)
KN03 ( Potassium Nitrate)-->The nitratete suffix corresponds to the highest number of nytrogen oxidation (+5)
Fe 2 (C03)3 (Iron (III) Carbonate / Dihydrous Trioxide / Ferric Carbonate)-->The carbonate suffix corresponds to the highest number of carbon oxidation (+4)
Pb (Co2)2 (Lead carbonate (IV) / Lead trioxocarbonate (IV)))-->The carbonate suffix corresponds to the highest number of carbon oxidation (+4)
Answer:
0.4589J/g°C
Explanation:
Heat energy = 1050J
Mass of iron = 220.0g
Initial temperature (T1) = 10°C
Final temperature (T2) = 20.4°C
Heat energy = mc∇T
Q = mc∇T
Q = heat energy
M = mass of the substance
C = specific heat capacity of the substance
∇T = change in temperature = T2 - T1
Q = m×c×(T2 - T1)
1050 = 220 × c ×(20.4 - 10)
1050 = 220c × (10.4)
1050 = 2288c
c = 1050 / 2288
C = 0.4589J/g°C
The specific heat capacity of iron is 0.4589J/g°C
A noble metal is a metal that resists oxidation and does not corrode (i.e: rust). Silver and platinum are great examples since they don't rust
