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2 years ago

The molar mass of CO2 is 44g/mol. How many grams are in 3 mol CO,?

Chemistry

2 answers:

pochemuha2 years ago

6 0

Answer:

We assume you are converting between moles CO2 and gram. You can view more details on each measurement unit: molecular weight of CO2 or grams This compound is also known as Carbon Dioxide. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CO2, or 44.0095 grams.

weqwewe [10]2 years ago

5 0

Answer:

Assuming the question was about 3 mol CO2 - it's 132g. Assuming it's about CO - it's 84g.

Explanation:

The molar mass of X means "a mole of X weighs that".

So 1 mol CO2 weighs 44g, so 3 moles will weigh three times that - 132g.

Now, with CO, we need to compute the molar mass of CO. One particle of CO is comprised of 2 atoms - a Carbon atom and an Oxygen atom, with molar masses ~12g and ~16g respectively. That brings us to molar mass of CO of 28g and the mass of 3 mol CO of 28g*3 = 84g

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a solution with a transmittance of 0.44 is analyzed in a spectrophotometer with 6% stray light. calculate the absorbance reporte

IgorLugansk [536]

The absorbance reported by the defective instrument was 0.3933.

Absorbance A = - log₁₀ T

Tm = transmittance measured by spectrophotometer

Tm = 0.44

Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654

True absorbance can be calculated by true transmittance, Tm = T+S(α-T)

S = fraction of stray light = 6%= 6/100 = 0.06

α= 1, ideal case

T = true transmittance of the sample

Tm = T+S(α-T)

now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233

therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)

i.e; 0.3933

To know more about transmittance click here:

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3 0

1 year ago

Simplify: (100 m)/(26 s)

podryga [215]

100m/26s=50m/13s

50m/13s=3.846m/s

4 0

3 years ago

Read 2 more answers

: Please predict products, label the states and write ionic and net ionic equations for each. These are all double replacement r

Mnenie [13.5K]

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4 0

3 years ago

A 44% wt/wt solution of H2SO4 has a density of 1.343g/ml. What mass of H2SO4 is 60ml of this solution?

horsena [70]

Answer: The mass of sulfuric acid present in 60 mL of solution is 34.1 grams

Explanation:

We are given:

44 % (m/m) solution of sulfuric acid. This means that 44 grams of sulfuric acid is present in 100 grams of solution.

To calculate volume of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.343 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

$1.343g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.343g/mL}=77.46mL$

To calculate the mass of sulfuric acid present in 60 mL of solution, we use unitary method:

In 77.46 mL of solution, mass of sulfuric acid present is 44 g

So, in 60 mL of solution, mass of sulfuric acid present will be = $\frac{44g}{77.46mL}\times 60mL=34.1g$

Hence, the mass of sulfuric acid present in 60 mL of solution is 34.1 grams

3 0

3 years ago

a titration of 25.0mL of an x M hcl solution with 0.15M NaOH starts at a burette reading for NaOH of 0.20mL . Thr burette readin

VARVARA [1.3K]

Burette is a very accurate measuring instrument when adding solutions and has a measurement error of 0.05 mL.
Small volumes of solutions can be transferred from the burette at a controllable rate.
In this instance NaOH is in the burette.
Initial reading of NaOH is 0.20 mL
end point is the point at which the chemical reaction reaches completion. In acid base reactions, end point is when all the H⁺ ions have reacted with OH⁻ ions.
final reading of NaOH is 24.10 mL
to find the volume of NaOH dispensed we have to find the difference between final reading and initial reading
volume of NaOH added = 24.10 mL - 0.20 mL = 23.90 mL
volume of NaOH dispensed is 23.90 mL

6 0

3 years ago