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3 years ago

The molar mass of CO2 is 44g/mol. How many grams are in 3 mol CO,?

Chemistry

2 answers:

pochemuha3 years ago

6 0

Answer:

We assume you are converting between moles CO2 and gram. You can view more details on each measurement unit: molecular weight of CO2 or grams This compound is also known as Carbon Dioxide. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CO2, or 44.0095 grams.

weqwewe [10]3 years ago

5 0

Answer:

Assuming the question was about 3 mol CO2 - it's 132g. Assuming it's about CO - it's 84g.

Explanation:

The molar mass of X means "a mole of X weighs that".

So 1 mol CO2 weighs 44g, so 3 moles will weigh three times that - 132g.

Now, with CO, we need to compute the molar mass of CO. One particle of CO is comprised of 2 atoms - a Carbon atom and an Oxygen atom, with molar masses ~12g and ~16g respectively. That brings us to molar mass of CO of 28g and the mass of 3 mol CO of 28g*3 = 84g

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3 years ago

To which orbitals may 5d electrons make spectroscopic transitions in a hydrogenic atom?

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Answer:

A. np and nf

Explanation:

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3 years ago

How many moles of H2s are produced when 2.25 moles Hcl react with excess zns

svlad2 [7]

Answer:

1.125 moles of H2S

Explanation:

From 2HCl(aq) + ZnS(s) ---------> H2S (g) + ZnCl2 (aq)

From the reaction equation;

2 moles of HCl produces 1 mole of H2S

Therefore 2.25 moles of HCl will produce 2.25 ×1/2 = 1.125 moles of H2S

Recall that it was explicitly stated in the question that ZnS is the reactant in excess. This implies that HCl is the limiting reactant and controls the amount of product obtained.

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3 years ago

What pattern do you observe in the coefficients of the hydrocarbon (CxHy) and water (H2O)? How do you explain this pattern?

balu736 [363]

The coefficients of the hydrocarbon and water is 61 and it is explained below.

Explanation:

We have to balance the chemical equation that describes the combustion of octane C₈H₁₈. The combustion of octane involves burning this hydrocarbon in the presence of excess oxygen,O 2. Because octane is a hydrocarbon, that is the compound that contains only carbon and hydrogen, the reaction will produce two products carbon dioxide CO 2 and water H 2 O.

The unbalanced chemical equation is

C₈H₁₈ + O₂ → CO₂ + H₂O

To balance this equation, we have 8 present on the reactant side, so multiply the carbon dioxide by 8 to get 8 atoms of carbon on the products side.

C₈H₁₈ + O₂ → 8 CO₂ + H₂O

Now, we have 18 on the reactant side and 2 on the products side, so multiply the water molecule by 9 to get

C₈H₁₈ + O₂ → 8 CO₂ + 9 H₂O

8 * 2 atoms O + 9 *1 atoms O = 25 atoms O

By adding fractional coefficient to O₂ we get

C₈H₁₈ + $\frac{25}{2}$ O₂ → 8 CO₂ + 9 H₂O

Multiply all the coefficients by 2 we get,

2C₈H₁₈ + ( $\frac{25}{2}$ * 2) O₂ → 8 * 2 CO₂ + 9* 2 H₂O

The balance equation is

2C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O

Add the coefficients to get their sum

= 2 +25 + 16 +18 = 61

Thus, The coefficients of the hydrocarbon and water is 61

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3 years ago