2. Which of these combinations of elements are most likely to react to form ionic compounds?

How many moles of carbon dioxide gas can be produced when 12.8 moles of benzene (C6H6) react with excess oxygen? Unbalanced equa

swat32

Answer: 76.8 mole

Explanation:

Firstly, the balanced equation of reacting benzene with excess oxygen is:

2C6H6 + 15O2 → 6H2O + 12CO2

It is clear that every two moles of benzene react with 15 mole of oxygen to produce 6 moles of water and 12 mole of CO2

Which means that 2 moles of benzene give 12 moles of CO2

So, n(C6H6)/2 = n(CO2)/12

which give n(C6H6) = n(CO2)/6

n(CO2) = n(C6H6) x 6 = 12.8 x 6 = 76.8 mole

6 0

3 years ago

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What is the ionic equation for the following<br> 2FeCl(aq)<br> 3Mg(s)<br> 3MgCl(aq)<br> 2Fe(s)

amid [387]

Answer : The net ionic equation will be,

$2Fe^{3+}(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+2Fe(s)$

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

$2FeCl_3(aq)+3Mg(s)\rightarrow 3MgCl_2(aq)+2Fe(s)$

The ionic equation in separated aqueous solution will be,

$2Fe^{3+}(aq)+6Cl^{-}(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+6Cl^{-}(aq)+2Fe(s)$

In this equation, $Cl^{-}$ is the spectator ion.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$2Fe^{3+}(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+2Fe(s)$

7 0

3 years ago

C6H12O6 is the formula for a sugar molecule.molecules are classified as?

expeople1 [14]

Answer:

D-Glucose

Explanation:

8 0

2 years ago

Determine the oxidation number of<br>Sulphur in Sodium thiosulphate

Semenov [28]

The oxidation number of Sulphur = +2

<h3>Further explanation</h3>

General formula for determining Oxidation Numbers :

1. The number of oxidation of single element atoms = 0. Examples of Ar, Mg, Cu, Fe, N₂, O₂, etc. = 0

Group I : +1

Group II : +2

H in compound = +1, except metal hydride compounds (Hydrogen which binds I or II groups) oxidation number H = -1, for example, LiH, MgH₂, etc.

2. Oxidation number O in compound = -2, except OF2 = + 2 and in peroxide (Na₂O₂, BaO₂) = -1 and superoxide, for example KO₂ = -1/2.

3 The oxidation number in a non-filled compound = 0,

The total amount of oxidation in ion = ion charge, Example NO₃⁻ = -1

Sodium thiosulphate - Na₂S₂O₃

Oxidation number Na = +1 ⇒x2 = +2

Oxidation number O = -2 ⇒x3 = -6

Oxidation number Na₂S₂O₃ = 0

2.Na+2.S+3.O=0

2.+1+2.S+3.(-2)=0

2+2S-6=0

-4+2S=0

2S=4

S=+2

4 0

3 years ago

What are the main functions of the human skeletal system?

laiz [17]

Answer:

The answer is A.........

3 0

3 years ago

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