Answer:
2,4,6-tri-tert-butylcyclohexa-2,5-dienone
Explanation:
1. Information from the formulas
C₁₈H₃₀O ⟶ C₁₈H₂₉BrO
A Br has replaced an H.
2. Information from the reaction
These look like the conditions for an electrophilic aromatic substitution.
3. Possible mechanism (Fig. 1)
The product must be highly symmetrical, because there are so few NMR signals.
(i) The bromonium ion attacks at the para position, forming a resonance-stabilized carbocation intermediate.
(ii) A bromide ion attacks the H of the hydroxyl group to form 2,4,6-tri-tert-butylcyclohexa-2,5-dienone.
4. Confirmatory evidence (Fig. 2)
(a) Infrared
1630 cm⁻¹: C=O stretch
1655 cm⁻¹ : C=C stretch
(b)NMR
1.2 (9h, s): the 4-tert-butyl group
1.3 (18H, s): the 2- and 6- tert- butyl groups
6.9 (2H, s): the alkene H atoms
The ratio is 9:18:2.
