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Varvara68 [4.7K]

3 years ago

7

Consider the following reaction in a closed system: H¿(g) + I¿(g) d 2HI(g) Which of the following will decrease the rate of the

forward reaction?

1 answer:

VladimirAG [237]3 years ago

4 0

Increase the volume of gas particles of H2 and of I2 will decrease the rate of the reaction.

If correct please mark it as brainiest.
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Proton-6 Neutron-7 Electron-6

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(55*10+56*20+57*70)/100=56.6

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3 years ago

1 mole of any gas is equivalent to?

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Answer:

22.4 L at standard temperature and pressure.

6 0

3 years ago

Explain, in your own words, why different elements produce different colors of light when heated.

fgiga [73]

Different elements produce different colors of light when heated because the electrons in these elements have different permissible energy levels. When an element is heated, the electrons inside it become excited and move to an higher energy level from the ground state. When the electrons drop from this higher energy level, they typically emit energy quantum, the color of the light that is observed at this stage depends on difference that exist in the two energy levels.<span />

7 0

2 years ago

Read 2 more answers

How much heat is needed warm 65.34 g of water from 18.43 to 21.75

BaLLatris [955]

Given that

Mass of water = 65.34 g

Amount of heat = mass of water * specific heat (temperature change

)

= 65.34 g * 4.184 J / g-C ( 21.75-18.43 )C

= 907.63 J

= 0.908 KJ

And

1 cal = 4.186798 J

907.63 J * 1 cal / 4.186798 J =216.78 cal

Or0.218 kcal

5 0

3 years ago

If 842 grams of sodium hydroxide reacts with 750.0 grams of aluminum, how many grams of aluminum hydroxide should theoretically

Phantasy [73]

548.55 grams of aluminum hydroxide should theoretically form.

Explanation:

Balanced equation for the reaction:

3 NaOH + Al ⇒ Al(OH)3 +3 Na

DATA GIVEN:

mass of NaOH = 842 grams, atomic mass =39.9 grams/mole

mass of Al = 750 grams, atomic mass = 26.9 grams/mole

aluminum hydroxide theoretical yield = ?

Moles of NaOH reacted

number of moles = $\frac{mass}{atomic mass of 1 mole}$

putting the values in the equation

NaOH = $\frac{842}{39.9}$

= 21.1 MOLES OF NaOH

Al = $\frac{750}{26.9}$

= 27.8 moles

from the equation

from 3 moles of NaOH 1 mole of Al(OH)3 is produced

21.1 moles of NaOH will react to give x moles of Al(OH)3

$\frac{1}{3}$ = $\frac{x}{21.1}$

7.03 moles of Al(OH)3 is formed.

and

1 mole of Al(OH)3 is formed from 1 mole of Al in the reaction

so, 27.8 Moles will react to give give 27.8 moles of Al(OH)3 limiting reagent of the given reaction is NaOH

mass of Al(OH)3 =7.03 x 78 (atomic mass of Al(OH)3)

= 548.55 grams

theoretical yield from the given data is 548.55 grams

3 0

2 years ago