Answer:
Cystic fibrosis (CF) is a genetic disease that causes thick, sticky mucus to build up in organs, including the lungs and the pancreas. In a healthy person, mucus that lines organs and body cavities, such as the lungs and the nose, is slippery and watery. In people with CF, thick mucus clogs causes symptoms in the lungs and pancreas.
Explanation:
The causes of CF
Who is affected
Symptoms and treatments
How CF is diagnosed in children and adults
Tips on living with CF
Answer:
A. The partial pressure for CH4 = 0.0925atm
B. The partial pressure for C2H6 = 0.925atm
C. The partial pressure for C3H8 = 0.346atm
D. The partial pressure for C4H10 = 0.115atm
Explanation:
Total pressure = 1.48atm
Total mole = 0.4+4+1.5+0.5=6.4
A. Mole fraction of CH4 = 0.4/6.4 = 0.0625
The partial pressure for CH4 = 0.0625 x 1.48 = 0.0925atm
B. Mole fraction of C2H6 = 4/6.4 = 0.625
The partial pressure for C2H6 = 0.625 x 1.48 = 0.925atm
C. Mole fraction of C3H8 = 1.5/6.4 = 0.234
The partial pressure for C3H8 = 0.234 x 1.48 = 0.346atm
D. Mole fraction of C4H10 = 0.5/6.4 = 0.078
The partial pressure for C4H10 = 0.078 x 1.48 = 0.115atm
<span>Mimicupcakes650 Beginner answered 5 minutes ago ... What would happen to the equilibrium mixture if the chlorine gas was allowed to escape? (explain your answer ) from Gabbymarriott. 1 answer ... Describe the physical and chemical properties of the raft that would be important to ensure your safety. from Dustyy.</span>
Answer:
Number of moles of oxygen = 0.037 mol
Explanation:
Given data:
Total pressure = 98.5 KPa
Partial pressure of nitrogen = 22.0 KPa
Partial pressure of argon = 50.0 KPa
Volume = 3.5 L
Temperature = 25°C (25+273= 298K)
Number of moles of oxygen = ?
Solution:
Total pressure = P(N₂) + P(O₂) + P(Ar)
98.5 KPa = 22.0 KPa +P(O₂) + 50.0 KPa
98.5 KPa = 72.0 KPa +P(O₂)
P(O₂) = 98.5 KPa - 72.0 KPa
P(O₂) = 26.5 KPa
KPa to atm:
26.5 KPa/ 101 = 0.262 atm
Number of moles of oxygen:
PV = nRT
n = PV/RT
n = 0.262 atm × 3.5 L / 0.0821 atm.L/mol.K × 298 K
n = 0.917atm.L /24.47atm.L/ mol
n = 0.037 mol
