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Damm [24]
3 years ago
5

Which state of matter takes the shape but NOT the volume of its container?

Chemistry
2 answers:
FinnZ [79.3K]3 years ago
6 0

Answer:

liquid is the state of matter that has a definite volume but takes the shape of its container

Mumz [18]3 years ago
3 0

Answer:

solids and liquids

Explanation:

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Can you think of other solutions that might be<br> acidic?
bija089 [108]

Answer:

i think the answer is yess

3 0
3 years ago
Read 2 more answers
Nitrogen and hydrogen combine to form ammonia.
zhenek [66]

The balanced chemical equation for the formation ammonia is

    N2(g) + 3H2(g)  ----> 2NH3(g)  .        

The balanced chemical equations explains that the same number of each element exist as reactants and products.  The coefficients in a balanced equation must be the simplest whole number ratio. Mass is always conserved in chemical reactions.

For the formation of ammonia, the chemical equation is

     N2(g) + H2(g)  ----> NH3(g)

Balancing the chemical reaction, we can write,

  N2(g) + 3H2(g)  ----> 2NH3(g)  .  

This equation shows two nitrogen entering the reaction together and two hydrogens entering the reaction together. Since NH3 is multiplied by a coefficient of 2 there are now 2 nitrogen and 6 hydrogens. The 6 hydrogens come from the 2 multiplied by the subscript of 3. This is the balanced chemical reaction.

To learn more about Balanced chemical equation please visit:

brainly.com/question/14072552

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6 0
1 year ago
What is the empirical formula for glucose<br> A)<br> B)<br> C)<br> D)
pshichka [43]
The Answer is A CH2O

The molecular formula for glucose is C6H12O6. The subscripts represent a multiple of an empirical formula. To determine the empirical formula, divide the subscripts by the GCF of 6 which gives CH2O.
4 0
3 years ago
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What mass of oxygen must react in order for 4.25 grams of CO2 to be produced? HELP
FromTheMoon [43]
When methane gas, CH4, burns completely in oxygen, the reaction produces carbon dioxide and water, as seen in the equation. CH4+2 O2 CO2 + 2 H20.
5 0
3 years ago
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A hot 123.3 g lump of an unknown substance initially at 164.2 °C is placed in 35.0 mL of water initially at 25.0 °C and the syst
Anuta_ua [19.1K]

Answer:

The unknown substance is rhodium.

Explanation:

Heat lost by hot substance will be equal to heat gained by the water

-Q_1=Q_2

Mass of substance= m_1=123.3 g

Specific heat capacity of substance= c_1=?

Initial temperature of the substance = T_1=164.2^oC

Final temperature of substance= T_2=T=48.6^oC

Q_1=m_1c_1\times (T-T_1)

Mass of water = M

Volume of water ,V= 35 ml

Density of water = d = 1.00 g/mL

M=d\times V=1.00 g/ml\times 35 mL=35 g

Mass of water= M = m_2=35 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=25.0^oC

Final temperature of water = T_3=T=48.6^oC

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

we get, c_1 =0.242 J/g^oC

The value of heat capacity of the substance is equal to that of rhodium metal.Hence, the unknown substance is rhodium.

4 0
3 years ago
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