Pls help me will mark Brianliest!!! I know the answer choice is a bit cut off. Topic is chem equilibrium

Chemistry

1 answer:

Svetlanka [38]3 years ago

6 0

Answer:

See notes on LeChatlier's Principle I gave you yesterday.

Explanation:

Remember chemical see-saw => Removing Fe⁺³ makes the reactant side of the see-saw lighter causing the balance to tilt right then shift left to establish a new equilibrium with new concentration values. Such would result in a decrease in FeSCN⁺² concentration and increases in Fe⁺³ and SCN⁻ concentrations to replace the original amount of ppt'd Fe⁺³. => Answer Choice 'B' ... Also, see attached => Concentration effects on stability of chemical equilibrium .

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1. In the investigation of an unknown alcohol, there was a positive Jones test and a negative Lucas test. What deductions may be

pogonyaev

Answer:

1. When observing a positive test for the jones reagent and negative for the Lucas test, it indicates that it is in the presence of a primary alcohol.

Jones reagent behaves like a strong oxidant, where it transforms the primary alcohols into carboxylic acids and the secondary alcohols into ketones. Tertiary alcohols do not react.

With the Lucas test, tertiary alcohols react immediately producing turbidity, while secondary alcohols do so in five minutes. Primary alcohols do not react significantly with Lucas reagent at room temperature.

2. No reaction (See the attached drawing)

3. (see the attached drawing)

7 0

3 years ago

Someone help 6th grade science i will give brainliest

patriot [66]

I believe the answer is C

3 0

3 years ago

Read 2 more answers

Determine the hybrid orbital of this molecule.

Pavel [41]

The hybrid orbital of this molecule is $sp^3$ . Hence, option C is correct.

<h3>What is hybridisation?</h3>

Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.

In this compound, $sp^3$ a hybrid orbital makes I-O bonds. Due to $sp^3$ hybridization iodate should have tetrahedral geometry but because of the presence of lone pair of electrons the shape of $IO^{3-}$ the ion is pyramidal.