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Sati [7]
3 years ago
12

Which of the following is a true statement about learning?

Physics
1 answer:
Furkat [3]3 years ago
3 0

Answer:

B. learning happens through experience and practice.

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Effieiency of simple machine is always less than 100% why​
zysi [14]

Answer:

efficiency of a machine is less than 100% because some part is energy is utilized to overcome some opposing forces like friction which is wasted as heat ,sound energy etc

Explanation:

8 0
3 years ago
What is concave mirror​
Licemer1 [7]

Answer:

A curved mirror is a mirror with a curved reflecting surface. The surface may be either convex or concave. Most curved mirrors have surfaces that are shaped like part of a sphere, but other shapes are sometimes used in optical devices.

Explanation:

8 0
4 years ago
A question for the physicists out there:
Tomtit [17]
I don't think that's exactly what this website is here for. / / / The average current = 30 C / 120 sec = 250 mA. / / / 1 volt = 1 joule/coulomb ... 30 C x 1.5 x 10^6 J/C = 4.5 x 10^7 joules per stroke. / / / Apoligies for the formatting. Some websites recognize a CR-LF from a mobile device, and others don't.
7 0
4 years ago
A 0.50 kg object is at rest. A 2.88 N force to the right acts on the object during a time interval of 1.48 s. a) What is the vel
Murljashka [212]

Answer:

8.5m/s

Explanation:

We are given that

Mass of object=m=0.50 kg

Initial velocity, u=0

Force=F=2.88 N

Time=1.48 s

a.We know that

F=ma

Using the formula

2.88=0.50a

a=\frac{2.88}{0.50}=5.76m/s^2

a=\frac{v-u}{t}

Using the formula

5.76=\frac{v-0}{1.48}

v=5.76\times 1.48=8.5m/s

Hence, the velocity of the object at the end of this time interval=8.5m/s

8 0
3 years ago
What is the relation between the wavelength, λ, and the momentum, p, of a particle? Roughly what kinetic energy should an electr
prisoha [69]

Answer:

λ = h/p

<u>E=2.41*10^{-17}Joules</u>

This energy is equivalent to E=150.44eV

Explanation:

<u>de Broglie Equation:</u>

λ = h/p

h=6.63×10-34 m2 kg / s        Planck's constant

so: p=h/λ

On the other hand, an atomic distance, an angstrom, is equal:10^{-10}m, λ should be similar to this distance.

<u>Kinetics Energy of a electron, m=9.11×10−31 kg</u>

<u>E=\frac{p^{2}}{2m_e}=\frac{h^{2}}{2\lambda^{2}m_e} =\frac{(6.63*10^{-34})^{2}}{2*(10^{-10})^{2}*9.11*10^{-31}}=2.41*10^{-17}Joules</u>

<u>Number of volts needed to accelerate that electron from rest to this energy:</u>

E=Vq_{e}

V=E/q_{e}=2.41*10^{-17}/(1.602*10^{-19})=150.44Volts

So, this energy is equivalent to E=150.44eV

This high-voltage device is called: particles accelerator

7 0
3 years ago
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