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3 years ago

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When a driver hits the brakes, his car decelerates from 50m/s at a uniform rate of 2.0m/s^2. His car stops after covering some d

istance. How long does it take him to stop?

1 answer:

Assoli18 [71]3 years ago

7 0

Please find attached photograph for your answer. Please do comment whether it is useful or not.

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A strong lightning bolt transfers an electric charge of about 16 C to Earth (or vice versa). How many electrons are transferred?

zzz [600]

Answer:

Number of electrons, $n=9.98\times 10^{19}$

Explanation:

A strong lightning bolt transfers an electric charge of about 16 C to Earth, q = 16 C

We need to find the number of electrons that transferred. Let there are n electrons transferred. It is given by using quantization of electric charge as :

q = ne

$n=\dfrac{q}{e}$

e is elemental charge

$n=\dfrac{16}{1.602\times 10^{-19}}$

$n=9.98\times 10^{19}$

So, there are $9.98\times 10^{19}$ electrons that gets transferred. Hence, this is the required solution.

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3 years ago

PLEASE HELP!! 13 POINTS! SCIENCE!

pogonyaev

Answer:

A.

Explanation:

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3 years ago

Read 2 more answers

A 1500-kg car locks its brakes and skids to a stop on a slippery horizontal road, leaving skid marks that are 15 m long. How muc

Harman [31]

Answer:

$E=88200\ J$

Explanation:

Given:

mass of car, $m=1500\ kg$

distance of skidding after the application of brakes, $d=15\ m$

coefficient of kinetic friction, $\mu_k=0.4$

<u>So, the energy dissipated during the skidding of car:</u>

<em>Frictional force:</em>

$f=\mu_k.N$

where N = normal reaction by ground on the car

$f=0.4\ties 1500\times 9.8$

$f=5880\ N$

<em>Now from the work-energy equivalence:</em>

$E=f.d$

$E=5880\times 15$

$E=88200\ J$ is the dissipated energy.

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3 years ago

Evaluate x and y in the equation: E=Cm^xV^y , where E is kinetic energy , m is mass , V is velocity and C is a dimension less co

Korvikt [17]

Answer: Do I look like Einstein

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2 years ago

What is the frequency of light with a wavelength of 7.9 x 10^-9 m? ( the speed of light is 3.00 x 10^8)

nlexa [21]

Using the formula v=f times lambada
then v=the speed of light.
and f=what’s we’re looking for
and lambada=the wavelength.

so then you sub what you have (v and lambada) in the formula.
then multiply the frequency(f) by the given wavelength and then solve for f

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2 years ago