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g100num [7]
3 years ago
13

When a driver hits the brakes, his car decelerates from 50m/s at a uniform rate of 2.0m/s^2. His car stops after covering some d

istance. How long does it take him to stop?
Physics
1 answer:
Assoli18 [71]3 years ago
7 0

Please find attached photograph for your answer. Please do comment whether it is useful or not.

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A strong lightning bolt transfers an electric charge of about 16 C to Earth (or vice versa). How many electrons are transferred?
zzz [600]

Answer:

Number of electrons, n=9.98\times 10^{19}

Explanation:

A strong lightning bolt transfers an electric charge of about 16 C to Earth, q = 16 C

We need to find the number of electrons that transferred. Let there are n electrons transferred. It is given by using quantization of electric charge as :

q = ne

n=\dfrac{q}{e}

e is elemental charge

n=\dfrac{16}{1.602\times 10^{-19}}

n=9.98\times 10^{19}

So, there are 9.98\times 10^{19} electrons that gets transferred. Hence, this is the required solution.

3 0
3 years ago
PLEASE HELP!! 13 POINTS! SCIENCE!
pogonyaev

Answer:

A.

Explanation:

3 0
3 years ago
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A 1500-kg car locks its brakes and skids to a stop on a slippery horizontal road, leaving skid marks that are 15 m long. How muc
Harman [31]

Answer:

E=88200\ J

Explanation:

Given:

  • mass of car, m=1500\ kg
  • distance of skidding after the application of brakes, d=15\ m
  • coefficient of kinetic friction, \mu_k=0.4

<u>So, the energy dissipated during the skidding of car:</u>

<em>Frictional force:</em>

f=\mu_k.N

where N = normal reaction by ground on the car

f=0.4\ties 1500\times 9.8

f=5880\ N

<em>Now from the work-energy equivalence:</em>

E=f.d

E=5880\times 15

E=88200\ J is the dissipated energy.

3 0
3 years ago
Evaluate x and y in the equation: E=Cm^xV^y , where E is kinetic energy , m is mass , V is velocity and C is a dimension less co
Korvikt [17]

Answer: Do I look like Einstein

8 0
2 years ago
What is the frequency of light with a wavelength of 7.9 x 10^-9 m? ( the speed of light is 3.00 x 10^8)
nlexa [21]
Using the formula v=f times lambada
then v=the speed of light.
and f=what’s we’re looking for
and lambada=the wavelength.

so then you sub what you have (v and lambada) in the formula.
then multiply the frequency(f) by the given wavelength and then solve for f

3 0
2 years ago
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