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Anika [276]
2 years ago
8

Using appropriate technology, you determine that Earth's magnetic field at your location has a magnitude of 5.88 10-5 T and is d

irected north at an angle of 56° below the horizontal. You charge a metallic projectile and fire it north with a speed of 663 m/s and at an angle of 14° above the horizontal. Determine the sign (+ or −) and charge of the projectile, if the magnetic force on the projectile is 3.22 10-10 N, directed due west.
C
Physics
1 answer:
Stolb23 [73]2 years ago
4 0

The sign (+ or −) and charge of the projectile, if the magnetic force on the projectile is 3.22 10-10 N, directed due west is mathematically given as

q=+1.11524613*10^{−4}C

<h3>What is the sign (+ or −) and charge?</h3>

Generally, the equation for Force is  mathematically given as

F=Bqvsin\theta

Therefore

3.22 10^{-10}= 5.88 10^{-5 } *633*sin 56*q\\\\q=\frac{3.22 10^{-10}}{5.88 10^{-5 } *633*sin 56}

q=+1.11524613*10^{−4}C

In conclusion, the sign (+ or −) and charge

q=+1.11524613*10^{−4}C

Read more about Charge

brainly.com/question/19886264

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Answer:

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Explanation:

We can find the heat necessary for the ice to go from -20 degrees Celsius to 0 degrees Celsius:

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We must calculate the latent heat of fusion required for this ice mass to change to water:

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Where H=334 J/g is the specific latent heat of fusion of water, that is the amount of energy needed per unit mass of a substance at its melting point to change from the solid to the liquid state.

Q=(350g)(334 J/g)=116900 J

Then we calculate the heat necessary for the water to go from 0 degrees Celsius to 20 degrees Celsius:

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Where c=4.18 J/g^{\circ}C is the specific heat of water, that is the amount of heat that must be supplied per unit mass to raise its temperature in a unit.

Q=(350g)(4.18 J/g^{\circ}C)(20^{\circ}C-0^{\circ}C)=29260 J

Finally the 3 results are added:

Q_{T}=14630 J + 116900 J + 29260 J=160790 J

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