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slamgirl [31]
2 years ago
12

Trivia Time!! At what velocity does light move?

Physics
2 answers:
Maslowich2 years ago
7 0

Explanation:

Light Light from a moving source travels at 300,000 km/sec (186,000 miles/sec).

Note:

The Speed of Light Is Constant.

Sauron [17]2 years ago
6 0

Explanation:

LIGHT TRAVELS AT A CONSTANT VELOCITY OF 300,000 km/sec.

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Yuri [45]

Answer:

Umm that's a personal question. All u have to do is say when have u pushed your personal limits....... Ummm one for me is when i had to try out for a select soccer and that is past my comfort zone.  

Explanation:

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3 years ago
What do scientists call water
pickupchik [31]

Answer:

h20

Explanation:

3 0
3 years ago
Read 2 more answers
A 4 kg bowling bowl is sitting on a table 1 meter off the ground. How much potential energy does it have?
il63 [147K]

Answer:

\huge\boxed{\sf P.E. = 39.2\ Joules}

Explanation:

<u>Given Data:</u>

Mass = m = 4 kg

Acceleration due to gravity = g = 9.8 m/s²

Height = h = 1 m

<u>Required:</u>

Potential Energy = P.E. = ?

<u>Formula:</u>

P.E. = mgh

<u>Solution:</u>

P.E. = (4)(9.8)(1)

P.E. = 39.2 Joules

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
5 0
3 years ago
A bolt falls off an airplane high above the ground. How far does the bolt have to fall before its speed reaches 100m/s (about 20
omeli [17]
We can use the equation vf (the final velocity) =vi (the initial velocity) +at (aceleration times time)

We know the final velocity 100m/s, the initial velocity 0, and the acceleration (gravity) 9.8m/s^2. So, 100=0+9.8t. t=100/9.8
3 0
3 years ago
An ideal air-filled parallel-plate capacitor has round plates and carries a fixed amount of equal but opposite charge on its pla
dusya [7]

Answer:

C). U_f = \frac{U_0}{2}

Explanation:

As we know that capacitance of a given capacitor is

C = \frac{\epsilon_0 A}{d}

now we know that energy stored in the capacitor plates

U_0 = \frac{Q^2}{2C}

here if all the dimensions of the capacitor plate is doubled

then in that case

C' = \frac{\epsilon_0 (4A)}{2d}

here area becomes 4 times on doubling the radius and the distance between the plates also doubles

So new capacitance is now

C' = 2C

so capacitance is doubled

now the final energy stored between the plates of capacitor is given as

U_f = \frac{Q^2}{2C'}

so the final energy is

U_f = \frac{Q^2}{4C}

U_f = \frac{U_0}{2}

4 0
3 years ago
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