Complete Question:
Ions to calculate the p-values: Na⁺, Cl⁻, and NH₄⁺
Answer:
pNa = 0.307
pCl = 0.093
pNH₄ = 0.503
Explanation:
The p-value is calculated by the antilog of the concentration of the substance of interest. For example, pH = -log[H⁺]. Thus, first, let's find the ions concentration.
Both substances are salts that solubilize completely, thus, by the solution reactions:
NaCl → Na⁺ + Cl⁻
NH₄Cl → NH₄⁺ + Cl⁻
So, for both reactions the stoichiometry is 1:1:1 and the concentration of the ions is equal to the concentration of the salts.
[Na⁺] = 0.493 M
[Cl⁻] = 0.493 + 0.314 = 0.807 M
[NH₄⁺] = 0.314 M
The p-values are:
pNa = -log[Na⁺] = -log(0.493) = 0.307
pCl = -log[Cl⁻] = -log(0.807) = 0.093
pNH₄ = -log[NH₄⁺] = -log(0.314) = 0.503
Answer:
The cathode is the electrode where the reduction takes place.
Explanation:
Cell has three components:
an electrolyte and two electrodes which is a cathode and an anode.
Electrolyte is usually solution of the water or other solvents in which the ions are dissolved.
<u>In electrolytic cell:</u>
Negatively charged electrode is the cathode where the process of reduction takes place.
Positively charged electrode is the anode where the process of oxidation takes place.
<u>In galvanic cell:</u>
Positively charged electrode is the cathode where the process of reduction takes place.
Negatively charged electrode is the anode where the process of oxidation takes place.
<u>So, the correct answer is - The cathode is the electrode where the reduction takes place.</u>
Ans: Elements in the same period have the same number of electron shells.
Answer:
4.21
Explanation:
use Avogadro's number
6.023 x 10^23
multiply this by 7 because you want to find 7 moles :
6.023 x 10^23 x 7 = 4.21
