Which of the following contains The greatest number of representative particles: 1 mole of water molecules, 1 mole of copper ato
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<u>Answer:</u> The mass of PVB required to produce 1000 grams of tape is 213.4 grams
<u>Explanation:</u>
To calculate the mass of aluminium oxide, we use the equation:
.......(1)
- <u>For
</u>
We are given:
50% (v/v) of
This means that 50 mL of aluminium oxide is present in 100 mL of tape
Calculating the mass of aluminium oxide by using equation 1:
Density of aluminium oxide =
Volume of aluminium oxide = (Conversion factor:
)
Putting values in equation 1, we get:
Mass of aluminium oxide = 199 g
- <u>For PVB:</u>
We are given:
50% (v/v) of PVB
This means that 50 mL of PVB is present in 100 mL of tape
Calculating the mass of PVB by using equation 1:
Density of PVB =
Volume of PVB =
Putting values in equation 1, we get:
Mass of PVB = 54 g
Mass of tape = Mass of aluminium oxide + mass of PVB
Mass of tape = [199 + 54] g = 253 g
To calculate the mass of PVB required to produce 1000 g of tape, we use unitary method:
When 253 grams of tape is made, the mass of PVB required is 54 g
So, when 1000 grams of tape is made, the mass of PVB required will be =
Hence, the mass of PVB required to produce 1000 grams of tape is 213.4 grams
The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.
A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.
where,
- i: van 't Hoff factor (1 for non-electrolytes)
- Kf: cryoscopic constant
- m: molality
The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:
The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.
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