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cricket20 [7]
3 years ago
8

Which of the following contains The greatest number of representative particles: 1 mole of water molecules, 1 mole of copper ato

ms, or 1 mole of sodium chloride ions?
a. 1 mole of copper atoms
b. 1 mole of sodium chloride ions
c. 1 mole of water molecules
d. none, they are all the same
Chemistry
1 answer:
Crazy boy [7]3 years ago
7 0

Answer:

1 mole of sodium chloride ions

Explanation:

i hope this answer helps u

plz mark me as brainliest

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How many moles of hcl are present in 40.0 ml of a 0.035 m solution?
Elden [556K]

Answer:

0.0014 moles is present in 40cm³ of 0.035M of HCl solution

Explanation:

Molarity = 0.035M

V = 40.0mL

1mL = 1cm³

V = 40cm³

0.035 moles = 1000cm³

X moles is present in 40cm³

X = (40 * 0.035) / 1000

X = 0.0014moles

0.0014 moles is present in 40cm³ of solution

8 0
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there are 1540 megawatts of wind-generated electricity produced globally every year. This amount is equivalent to how many kilow
Reptile [31]

1.54 x 10⁶kW

Explanation:

The problem here is converting from megawatts into kilowatts.

  Given 1540megawatts.

The mega- and kilo- watts are prefixes that denotes multiples of units.

  1 megawatt = 10⁶watts

  1 kilowatt = 10³watts

Now given 1540megawatts power to Kilowatt power;

   We see that :

   1000kW = 1mW

 1540mW x \frac{1000kW}{1mW} = 1.54 x 10⁶kW

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4 0
3 years ago
How do polar and nonpolar covalent bonds differ?
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Answer: In polar covalent bonds a pair of electrons are unequally shared between two atoms, while in nonpolar covalent bonds two atoms share a pair of electrons with each other.

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Explanation:

7 0
3 years ago
Whitch statement is the best example of pseudosicience
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7 0
3 years ago
A chemist prepares a solution of magnesium chloride MgCl2 by measuring out 49.mg of MgCl2 into a 100.mL volumetric flask and fil
Flura [38]

Answer:  Molarity of Cl^- anions in the chemist's solution is 0.0104 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.049g}{95g/mol}=5.2\times 10^{-4}moles  

V_s = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

Molarity=\frac{5.2\times 10^{-4}moles\times 1000}{100ml}=5.2\times 10^{-3}mole/L

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MgCl_2\rightarrow Mg^{2+}+2Cl^-

As 1 mole of MgCl_2 gives 2 moles of Cl^-

Thus 5.2\times 10^{-3}  moles of MgCl_2 gives =\frac{2}{1}\times 5.2\times 10^{-3}=0.0104

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6 0
3 years ago
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