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cricket20 [7]
3 years ago
8

Which of the following contains The greatest number of representative particles: 1 mole of water molecules, 1 mole of copper ato

ms, or 1 mole of sodium chloride ions?
a. 1 mole of copper atoms
b. 1 mole of sodium chloride ions
c. 1 mole of water molecules
d. none, they are all the same
Chemistry
1 answer:
Crazy boy [7]3 years ago
7 0

Answer:

1 mole of sodium chloride ions

Explanation:

i hope this answer helps u

plz mark me as brainliest

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A compound that contains only carbon, hydrogen, and oxygen is 58.8% C and 9.87% H by mass. What is the empirical formula of this
Dmitry [639]

<u>Answer:</u> The empirical formula of the compound becomes C_5H_{10}O_2

<u>Explanation:</u>

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

Let the mass of the compound be 100 g

Given values:

% of C = 58.8%

% of H = 9.87%

% of O = [100 - 58.8 - 9.87] = 31.33%

Mass of C = 58.8 g

Mass of H = 9.87 g

Mass of O = 31.33 g

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of C}=\frac{58.8g}{12g/mol}=4.9 mol

\text{Moles of H}=\frac{9.87g}{1g/mol}=9.87 mol

\text{Moles of O}=\frac{31.33g}{16g/mol}=1.96mol

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 1.96 moles

\text{Mole fraction of C}=\frac{4.9}{1.96}=2.5

\text{Mole fraction of H}=\frac{9.87}{1.96}=5.03\approx 5

\text{Mole fraction of O}=\frac{1.96}{1.96}=1

Converting the mole fraction into whole numbers by multiplying them with 2.

\text{Mole fraction of C}=2.5\times 2=5

\text{Mole fraction of H}=5\times 2=10

\text{Mole fraction of O}=1\times 2=2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 5 : 10 : 2

Hence, the empirical formula of the compound becomes C_5H_{10}O_2

8 0
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