Xf=?
Xi=0m
Vi=0m/s
Vf=40m/s
a=?
t=12s
Xf=Xi+1/2(Vi+Vf)t
Xf= 0 +1/2 (0+40)12
Xf=1/2 (40)12
Xf=240m
Vf=Vi+at
40=0+a (12)
40=12a
a=3.33m/s^2
By firing electrons from a cathode gun at a known velocity through an electric field of a known strength, J.J Thomson was able to observe how much the field deflected the beam. With a mass-to-charge ratio calculated, he could determine that the mass of the electron was not significantly heavy (in fact almost nothing compared to the proton or neutron)
Pluto is 4.67 billion miles away
Answer:
i) Angle of Reflection = Angle of Incident
ii) Total Angle = 2x Angle of reflection/incidence
iii) The incident ray, reflected ray and the point of incidence lie in the same plane
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Answer:
a)
b)
c) t = 2.031s X = 1.52m
Explanation:
Let X1 be position of car A as a function of time and X2 be the position of car B as a function of time:
X1 = Xo1 + V1*t If we evaluate this expression at t=t1
S1 = Xo1 + V1*t1 Solving for Xo1 we get its initial position at t=0:
Xo1 = S1 - V1*t1
Similarly for car B:
Xo2 = S2 - V2*t2
Now, to find the instant when car B overtakes car A:
X1 = X2 Replacing their functions in time:
(S1 - V1*t1) + V1*t = (S2 - V2*t2) + V2*t Solving for t:
This is the instant when B reaches A
If we replace this expression in either X1 or X2 expression, we get that position: X1 = X2
If we evaluate these two expressions with the given values:
t = 2.031s and X = 1.52m