Answer:
0.823 Nm
Explanation:
current, i = 100 A
radius, r = 10 cm
Angle between the normal and the magnetic field, θ = 30°
Magnetic field, B = 0.524 T
Torque is defined as the
Torque = 0.823 Nm
Thus, the torque is 0.823 Nm.
Answer:
The answer is 150,000
Explanation:
I got my answer by solving 10^5 which is 100,000 then you just multiply 1.5 to get 150,000
B. In step 3
They incorrectly solved for x. It should have been x=-3 and x=5
Recall the definition of the cross product with respect to the unit vectors:
i × i = j × j = k × k = 0
i × j = k
j × k = i
k × i = j
and that the product is anticommutative, so that for any two vectors u and v, we have u × v = - (v × u). (This essentially takes care of part (b).)
Now, given a = 8i + j - 2k and b = 5i - 3j + k, we have
a × b = (8i + j - 2k) × (5i - 3j + k)
a × b = 40 (i × i) + 5 (j × i) - 10 (k × i)
… … … … - 24 (i × j) - 3 (j × j) + 6 (k × j)
… … … … + 8 (i × k) + (j × k) - 2 (k × k)
a × b = - 5 (i × j) - 10 (k × i) - 24 (i × j) - 6 (j × k) - 8 (k × i) + (j × k)
a × b = - 5k - 10j - 24k - 6i - 8j + i
a × b = -5i - 18j - 29k
C.an equal and opposite reaction
