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egoroff_w [7]
3 years ago
6

Imagine that the ball on the left is given a nonzero initial velocity in the horizontal direction, while the ball on the right c

ontinues to fall with zero initial velocity. What horizontal speed vx must the ball on the left start with so that it hits the ground at the same position as the ball on the right? Express your answer in meters per second to two significant figures.
Physics
1 answer:
masya89 [10]3 years ago
7 0

Answer:

vₓ = xg/2y

Explanation:

In this question, let us  find the time it takes for the ball on the right that has zero initial velocity to reach the ground.

By newton equation of motion we know that

y = v₀ t - ½ g t²

t = 2y / g

This is the time it takes for the ball on the right to reach the ground; at this time the ball on the left travels a distance

vₓ = x/t

vₓ = xg/2y

vₓ = xg/2y

Where we assume that x and y are known.

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Answer:

a) θ₁ = 23.14 ° , b) θ₂ = 51.81 °

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An address network is described by the expression

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The distance between one lines, we can find used a rule of proportions

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First order

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Second order

     θ₂ = sin⁻¹ (2 6.5628 10⁻⁷ / 1.67 10⁻⁶)

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A man has a mass of 66 kg on the earth. What is his weight.
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What is the time it takes an object that moves at 25 m/min to travel 505 meters?
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