Write an equation: At 2 claps, Joe is in position 7 and walking towards zero at a rate of 3 claps per minute.

Mathematics

1 answer:

frutty [35]2 years ago

6 0

Answer:

I'll assume "position 7" refers to distance and not to the order of other people.

Step-by-step explanation:

We want an equation of the form y=mx+b, where m is the slope and b is the y-intercept (the value of y when x=0). We can assume that "claps" is a new measure of distance. 0 claps is the finish.

Let's express the information provided in point format.

"At 2 claps, Joe is in position 7" is (2,7) 2 is the distance (claps) and 7 is the time (minutes)

And we can say the rate is also the slope of a line. "rate of 3 claps per minute" is 3c/m, where c is claps and m is minutes.

We can start a line equation by stating y = 3x + b, where we're using the rate, 3 c/m, as the slope, m.

We need to determine the value of b. We can use the given point (2,7) and solve for m:

y = 3x + b

7 = 3*(2) + b

b = 1

The equation becomes y = 3x + 1

y is the distance in claps and x is the time in minutes.

At a time of 2 claps he is at position of 7. b = 1 means he started 1 clap further from the finish at 0 claps.

To find the time required to reach the finish, we need to know the total distance, in claps.

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C. z = 2.05

Step-by-step explanation:

We have to calculate the test statistic for a test for the diference between proportions.

The sample 1 (year 1995), of size n1=4276 has a proportion of p1=0.384.

$p_1=X_1/n_1=1642/4276=0.384$

The sample 2 (year 2010), of size n2=3908 has a proportion of p2=0.3621.

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The pooled proportion, needed to calculate the standard error, is:

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The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3735*0.6265}{4276}+\dfrac{0.3735*0.6265}{3908}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00006}=\sqrt{0.00011}=0.0107$