Answer:
a.
b.
c. Choice A- Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.
Step-by-step explanation:
a.Binomial distribution is defined by the expression

Let n be the number of trials,
and p be the probability of success,
The mean of a binomial distribution is the probability x sample size.

b.Limits within which p is approximately 95%
sd of a binomial distribution is given as:
Therefore, 
Use the empirical rule to find the limits. From the rule, approximately 95% of the observations are within to standard deviations from mean.

Hence, approximately 95% of the observations are within 7.8586 and 22.1414 (areas of infestation).
c.
is not within the limits in b above (7.8586,22.1414). X=45 appears to be a large area of infestation. A.Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.