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jenyasd209 [6]
3 years ago
14

Por que los egipcios podrían haber construido pirámides?

Chemistry
1 answer:
kicyunya [14]3 years ago
4 0
Eran monumentos funerarios, de manera que su principal función era la de acoger tumbas de los faraones para que el viaje al cielo fuese más sencillo
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Write a balanced net ionic equation to show why the solubility of Cu(OH)2(s) increases in the presence of a strong acid and calc
Helga [31]

Answer:

2.2×10^8

Explanation:

Cu(OH)2(s)<---------> Cu^2+(aq) + 2OH^-(aq) Ksp=2.2 x 10 ^-20

2H3O^+(aq) + 2OH^-(aq) <-------> 4H2O(l). Kw= 1×10^14

Cu^2+(aq) + 4H2O(l) <--------> [Cu(H2O)4]^2+(aq)

Overall ionic reaction:

Cu(OH)2(s) +2H3O^+(aq) <---------> [Cu(H20)4]^2+(aq)

Equilibrium constant for the reaction: Ksp×Kw= 2.2 x 10 ^-20 × (1/(1×10^-14))^2

Keq= 2.2×10^8

Kw= ion dissociation constant of water

3 0
3 years ago
What 3 categories are elements divided
cricket20 [7]
Classification of the Elements. The next thing in our review is to classify the elements into three groups. These three groups are: metals, nonmetals, and inert gases. Let's look at where these groups are located on the periodic table and correlate them with the ability to lose and gain electrons.
6 0
3 years ago
По сссстото пъпси и спп.<br> a. 120 mm =<br> What is 120 milliters to meters
Vera_Pavlovna [14]
120mm is equal to 0.12 meters
3 0
3 years ago
Which best summarize the results of Mendel's pea plant experience
Ludmilka [50]

Answer:

C

Explanation:

8 0
3 years ago
Read 2 more answers
CO(g)+2H2(g)⇌CH3OH(g)CO(g)+2H2(g)⇌CH3OH(g) This reaction is carried out at a different temperature with initial concentrations o
Katarina [22]

Answer:

9.4

Explanation:

The equation for the reaction can be represented as:

CO_{(g)}    +      2H_2O_{(g)}   ⇄  CH_3OH_{(g)}

The ICE table can be represented as:

                                  CO_{(g)}    +      2H_2_{(g)}   ⇄  CH_3OH_{(g)}

Initial                          0.27             0.49              0.0

Change                      -x                  -2x                 x

Equilibrium               0.27 - x         0.49 -2x          x

We can now say that the concentration of  CH_3OH_{(g)} at equilibrium is x;

Let's not forget that at equilibrium  CH_3OH_{(g)} = 0.11 M

So:

x =  [CH_3OH_{(g)}] = 0.11 M

[CO_{(g)}] = 0.27 - x

[CO_{(g)}] = 0.27 - 0.11

[CO_{(g)}] = 0.16 M

[2H_2_{(g)}] = (0.49 - 2x)

[2H_2_{(g)}] = (0.49 - 2(0.11))

[2H_2_{(g)}] = 0.49 - 0.22

[2H_2_{(g)}] = 0.27 M

K_C = \frac{[CH_3OH]}{[CO][H_2]^2}

K_C = \frac{(0.11)}{(0.16)[(0.27)^2}

K_C = 9.4307

K_C = 9.4

∴ The equilibrium constant at that temperature = 9.4

8 0
3 years ago
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