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Viktor [21]
3 years ago
12

Balance the equation 2Fe + 3Cl2 → 2FeCl3

Chemistry
1 answer:
Tresset [83]3 years ago
4 0

Answer:

6 Cl0 + 6 e- → 6 Cl-I (reduction)

2 Fe0 - 6 e- → 2 FeIII (oxidation)

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Which equation is derived from the combined gas law?
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3 years ago
How many parts per million of lead is found in 250 ml of water if there is 1.30g of lead in the water? 1ml=1g
SSSSS [86.1K]

Answer:

5200 ppm

Explanation:

As per the definition, parts per million of a contaminant is a measure of the amount of mass of contaminant present per million amount of the solution. It is denoted by ppm.

Given in the question,

Water = 250 ml = 250 g

Lead = 1.30 g

So,

ppm of Lead = \frac{Lead}{Water} \times 10^6 = \frac{1.30}{250} \times 10^6 = 5200 ppm

So, as calculated above, there is 5200 ppm of lead present in 250 ml of water.

6 0
3 years ago
Calculate the solubility of Mg(OH)2 in water at 25 C. You'll find Ksp data in the ALEKS Data tab. Round your answer to significa
elena-s [515]

Answer:

1.12 × 10⁻⁴ M

Explanation:

Step 1: Write the reaction for the solution of Mg(OH)₂

Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

Step 2: Make an ICE chart

We can relate the solubility product constant (Ksp) with the solubility (S) through an ICE chart.

       Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

I                                0                    0

C                              +S                +2S

E                                S                  2S

The solubility product constant is:

Ksp = 5.61 × 10⁻¹² = [Mg²⁺] × [OH⁻]² = S × (2S)² = 4S³

S = 1.12 × 10⁻⁴ M

8 0
3 years ago
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