Answer is: 79.8 grams of copper(II) sulfate.
N(CuSO₄) = 3.01·10²³; number of molecules.
n(CuSO₄) = N(CuSO₄) ÷ Na.
n(CuSO₄) = 3.01·10²³ ÷ 6.02·10²³ 1/mol.
n(CuSO₄) = 0.5 mol; amount of substance.
m(CuSO₄) = n(CuSO₄) · M(CuSO₄).
m(CuSO₄) = 0.5 mol · 159.6 g/mol.
m(CuSO₄) = 79.8 g; mass of substance.
M - molar mass.
Test tubes, flasks, bunsen burners, random chemical equations
The answer is Index fossils its the only answer it could be
Answer:
[H₃O⁺] = 6.31 x 10⁻³ M.
Explanation:
- To find the hydronium ion concentration [H₃O⁺], we can use the relation:
<em>pH = - log[H₃O⁺].</em>
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∴ 2.2 = - log[H₃O⁺].
∴ log[H₃O⁺] = - 2.2
<em>∴ [H₃O⁺] = 6.31 x 10⁻³ M.</em>
