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2 years ago

How does molecular shape affect polarity?

Chemistry

2 answers:

Andrej [43]2 years ago

6 0

Answer:

Letter D

Explanation:

stepladder [879]2 years ago

6 0

Answer:

An attraction between the positive end of one molecule and the negative end of another

Explanation:

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A solution contains 0.775 g Ca2 0.775 g Ca2 in enough water to make a 1925 mL1925 mL solution. What is the milliequivalents of C

Romashka [77]

Answer: There will be 0.00002 meq per Liter of the solution.

Explanation:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

$Normality=\frac{\text{no of gram equivalents} \times 1000}{\text{Volume in ml}}$

$Normality=\frac{\text{given mass}\times 1000}{\text {Equivalent mass}\times {\text{Volume in ml}}}$

Equivalent weight is calculated by dividing the molecular weight by n factor. ${\text{Equivalent weight}}=\frac{\text{Molecular weight}}{n}$

n= charge for charged species , For $Ca^{2+}$ , n =2

${\text{Equivalent weight}}=\frac{40}{2}=20g$

$\text{no of gram equivalents}=\frac{0.775g}{20g/mol}=0.04gramequivalents$

$Normality=\frac{0.04\times 1000}{1925}=0.02eq/L=0.00002meq/L$

Thus there will be 0.00002 meq per Liter of the solution.

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3 years ago

What quantity of sodium azide in grams is required to fill a 56.0 liters air bag with nitrogen gas at 1.00 atm and exactly 0 °C:

Margarita [4]

Answer:

108.6 g

Explanation:

2NaN₃(s) → 2Na(s) + 3N₂(g)

First we use the PV=nRT formula to calculate the number of nitrogen moles:

P = 1.00 atm

V = 56.0 L

n = ?

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = 0 °C ⇒ 0 + 273.2 = 273.2 K

Inputting the data:

1.00 atm * 56.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 273.2 K

n = 2.5 mol

Then we convert 2.5 moles of N₂ into moles of NaN₃, using the stoichiometric coefficients of the balanced reaction:

2.5 mol N₂ * $\frac{2molNaN_3}{3molN_2}$ = 1.67 mol NaN₃

Finally we convert 1.67 moles of NaN₃ into grams, using its molar mass:

1.67 mol * 65 g/mol = 108.6 g

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2 years ago