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Lady_Fox [76]
2 years ago
9

How does molecular shape affect polarity?

Chemistry
2 answers:
Andrej [43]2 years ago
6 0

Answer:

Letter D

Explanation:

stepladder [879]2 years ago
6 0

Answer:

An attraction between the positive end of one molecule and the negative end of another

Explanation:

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A solution contains 0.775 g Ca2 0.775 g Ca2 in enough water to make a 1925 mL1925 mL solution. What is the milliequivalents of C
Romashka [77]

Answer: There will be 0.00002 meq per Liter of the solution.

Explanation:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Normality=\frac{\text{no of gram equivalents} \times 1000}{\text{Volume in ml}}

Normality=\frac{\text{given mass}\times 1000}{\text {Equivalent mass}\times {\text{Volume in ml}}}

Equivalent weight is calculated by dividing the molecular weight by n factor.   {\text{Equivalent weight}}=\frac{\text{Molecular weight}}{n}

n= charge for charged species  , For Ca^{2+} , n =2

{\text{Equivalent weight}}=\frac{40}{2}=20g

\text{no of gram equivalents}=\frac{0.775g}{20g/mol}=0.04gramequivalents

Normality=\frac{0.04\times 1000}{1925}=0.02eq/L=0.00002meq/L

Thus there will be 0.00002 meq per Liter of the solution.

3 0
3 years ago
What quantity of sodium azide in grams is required to fill a 56.0 liters air bag with nitrogen gas at 1.00 atm and exactly 0 °C:
Margarita [4]

Answer:

108.6 g

Explanation:

  • 2NaN₃(s) → 2Na(s) + 3N₂(g)

First we use the <em>PV=nRT formula</em> to <u>calculate the number of nitrogen moles</u>:

  • P = 1.00 atm
  • V = 56.0 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 0 °C ⇒ 0 + 273.2 = 273.2 K

<u>Inputting the data</u>:

  • 1.00 atm * 56.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 273.2 K
  • n = 2.5 mol

Then we <u>convert 2.5 moles of N₂ into moles of NaN₃</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:

  • 2.5 mol N₂ * \frac{2molNaN_3}{3molN_2} = 1.67 mol NaN₃

Finally we <u>convert 1.67 moles of NaN₃ into grams</u>, using its <em>molar mass</em>:

  • 1.67 mol * 65 g/mol = 108.6 g
6 0
2 years ago
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