Answer:
The mass of tin is 164 grams
Explanation:
Step 1: Data given
Specific heat heat of tin = 0.222 J/g°C
The initial temeprature of tin = 80.0 °C
Mass of water = 100.0 grams
The specific heat of water = 4.184 J/g°C
Initial temperature = 30.0 °C
The final temperature = 34.0 °C
Step 2: Calculate the mass of tin
Heat lost = heat gained
Qlost = -Qgained
Qtin = -Qwater
Q = m*c*ΔT
m(tin)*c(tin)*ΔT(tin) = -m(water)*c(water)*ΔT(water)
⇒with m(tin) = the mass of tin = TO BE DETERMINED
⇒with c(tin) = the specific heat of tin = 0.222J/g°C
⇒with ΔT(tin) = the change of temperature of tin = T2 - T1 = 34.0°C - 80.0°C = -46.0°C
⇒with m(water) = the mass of water = 100.0 grams
⇒with c(water) = the specific heat of water = 4.184 J/g°C
⇒with ΔT(water) = the change of temperature of water = T2 - T1 = 34.0° C - 30.0 °C = 4.0 °C
m(tin) * 0.222 J/g°C * -46.0 °C = -100.0g* 4.184 J/g°C * 4.0 °C
m(tin) = 163.9 grams ≈ 164 grams
The mass of tin is 164 grams
theoretical yield of the reaction is 121.38 g of NH₃ (ammonia)
limiting reactant is N₂ (nitrogen)
excess reactant is H₂ (hydrogen)
Explanation:
We have the following chemical reaction:
N₂ + 3 H₂ → 2 NH₃
Now we calculate the number of moles of each reactant:
number of moles = mass / molar weight
number of moles of N₂ = 100 / 28 = 3.57 moles
number of moles of H₂ = 100 / 2 = 50 moles
From the chemical reaction we see that 3 moles of H₂ are reacting with 1 moles of N₂, so 50 moles of H₂ are reacting with 16.66 moles of N₂ but we only have 3.57 moles of N₂ available, so the limiting reactant will be N₂ and the excess reactant will be H₂.
Knowing the chemical reaction and the limiting reactant we devise the following reasoning:
if 1 mole of N₂ produce 2 moles of NH₃
then 3.57 moles of N₂ produce X moles of NH₃
X = (3.57 × 2) / 1 = 7.14 moles of NH₃
mass = number of moles × molar weight
mass of NH₃ = 7.14 × 17 = 121.38 g
theoretical yield of the reaction is 121.38 g of NH₃
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limiting reactant
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When formaldehyde and acetone then react with each other( aldol condensation) then it will be formed <u> methyl vinyl ketone.</u>
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In organic chemistry, an aldol condensation would be a condensation reaction in which an enol and enolate ion combines with a carbonyl chemical to produce a -hydroxy aldehyde or -hydroxy ketone, that is then dehydrated to produce a conjugated enone.
In aldol condensation, when formaldehyde and acetone then react with each other then it will be formed <u> </u><u>methyl vinyl ketone.</u>
It can be written as
→ 
When it will be heated then it gives methyl vinyl ketones.
→ 
So, the pair of reactants will be formaldehyde and acetone
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