Atoms contact with other atoms and rearrange themselves to create bonds.<span />
Hello! Rutherford’s gold foil experiment was actually really cool. While he put a beam of alpha particles into a sheet of gold foil, a few of those particles were easily deflected. He soon discovered that the reason those particles being deflected was because a little tiny nucleus. He was the one who found out the nuclear theory of an atom. I hope this was one of your answers. If not, feel free to message me and tell me your options. I’ll help you as much as I can. Have a great day! :)
2CuI (s) + I₂ (aq) → 2 Cu⁺² (aq) + 4 I⁻ (aq)
When writing an equilibrium expression, we use the following values:
A (aq) + 3B (aq) → 2C (aq) + 2D (aq)
The numbers were arbitrary molar equivalents and the uppercase letters are the molecules in the reaction. The species used in the equilibrium expression but all be in the same state, e.g., solid, liquid, aqeuous.
Kc = [C]²[D]² / [A][B]³
We write the formula by taking the concentration of the products, each to the power of their molar equivalent, and multiply them together. We then divide the products by the concentration of the reactants, also to the power of their molar equivalent.
Going back to the initial equation given, we can now write a Kc expression.
Kc = [Cu⁺²]²[I⁻]⁴ / [I₂]
It should be noted that the CuI (s) in the reaction was left out of the Kc expression. Pure solids and liquids are left out of the expression and only the aqueous species are included. The reason being that, in this case, solid CuI does not affect the amount of reactant at equilibrium. Therefore, we just leave the concentration for [CuI] = 1, and remove it from the expression.
Number of moles = 2.12 mol C3H8.
1 mol C3H8 = 6.02 × 1023 molecules C3H8.
<span>1 molecule C3H8 = </span>11 atoms.
(3 carbon atoms<span> and 8 hydrogen atoms)</span>
Answer:
[H⁺] = 0.000048936M
pH = 4.31
Explanation:
Acetic acid, CH₃COOH, dissociates in water as follows:
CH₃COOH(aq) ⇄ H⁺(aq) + CH₃COO⁻(aq)
And Ka is defined as:
Ka = 1.76x10⁻⁵ = [H⁺] [CH₃COO⁻] / [CH₃COOH]
<em>Where [] are equilibrium concentrations of the species.</em>
<em />
The 0.000185M of acetic acid will decreases X, and X of [H⁺] and [CH₃COO⁻] will be produced. That means Ka is:
1.76x10⁻⁵ = [X] [X] / [0.000185 - X]
3.256x10⁻⁹ - 1.76x10⁻⁵X = X²
3.256x10⁻⁹ - 1.76x10⁻⁵X - X² = 0
Solving for X:
X = -0.000066M → False solution. There is no negative concentrations.
X = 0.000048936
As [H⁺] = X,
[H⁺] = 0.000048936M
And pH = -log [H⁺]
<h3>pH = 4.31</h3>