Answer:
4.2 x 10⁴ mL
Explanation:
Data Given:
Density (d) of air = 1.19 x 10⁻³g/mL
Mass of the air (m) = 50 g
Volume of the air (V) = ?
Solution:
Formula will be used
d = m/V
As we have to find volume so rearrange the above equation
V = m/d . . . . . . . . . . . (1)
Put values in above equation 1
V = 50 g / 1.19 x 10⁻³g/mL
V = 4.2 x 10⁴ mL
So,
volume of dry air = 4.2 x 10⁴ mL
There are two things that could be done. The first is to increase the mass of the objects. The second is to decrease the distance between the center of masses of the objects.
Answer:
a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.
Explanation:
The heating curve is a curve that represents temperature (T) in the y-axis vs. added heat (Q) in the x-axis. The slope is T/Q = 1/C, where C is the heat capacity. Then, the higher the slope, the lower the heat capacity. For a constant mass, it can also represent the specific heat capacity (c).
Heats of vaporization and fusion cannot be calculated from these sections of the heating curve.
<em>Which statement below explains that?</em>
<em>a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.</em> YES.
<em>b. The specific heat capacity of the gaseous ethanol is greater than the specific heat capacity of liquid ethanol.</em> NO.
<em>c. The heat of vaporization of ethanol is less than the heat of fusion of ethanol.</em> NO.
<em>d. The heat of vaporization of ethanol is greater than the heat of fusion of ethanol.</em> NO.
You’re answer for this question would be b
Hihihihihihihihihihihihihi
Hibiscus I
Hi yes
