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Alex
2 years ago
14

Which of the following statements is true?

Physics
1 answer:
sweet-ann [11.9K]2 years ago
7 0

Answer:

D. Friction slow down or stop objects in motion.

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I need help with this one 2 if you guys don’t mind
zloy xaker [14]
3 is 3.81 meters

4 is 0.47 liters

5 is 4 cm

6 is 23 mm

7 is 53 m

8 is 1800 mg

9 is 31.07 mi

Hope I’m helping ya

6 0
3 years ago
The actual mechanical advantage of any machine is its__________divided by its________________
zaharov [31]

Answer: Load divided by it effort

Explanation:

Mechanical advantage of any machine is its load divided by its effort

4 0
3 years ago
Your brother bikes 350 miles in 27 seconds how fast did he go
Harrizon [31]
His speed is exactly (350/27) miles per second ... about 46,667 mph. Wotta guy !
6 0
3 years ago
A motor-driven winch pulls a 50.0 kg student 5.00 m up the rope at a constant speed of 1.25 m/s. how much power does the motor u
nadya68 [22]
Power is the rate work done given by dividing work done by unit time. It is measured in watts equivalent to J/s.
In this case the force by the student is mg = 490 N (taking g as 9.8m/s²)
Work done is given by force × distance,
Therefore, Power =(force × distance)/ time, but velocity/speed =distance/time
Thus, Power = force × speed/velocity
                     = 490 N × 1.25
                     = 612.5 J/S (Watts)
Hence, power will be 612.5 Watts.
7 0
3 years ago
Web Spiders and Oscillations All spiders have special organs that make them exquisitely sensitive to vibrations. Web spiders det
Leokris [45]

Answer:

0.037 N/m

Explanation:

The web acts as a spring, so it obeys Hook's law:

F=kx (1)

where

F is the force exerted on the web

k is the spring constant

x is the stretching/compression of the web

In this problem, we have:

- The mass of the fly is m=15 mg=15\cdot 10^{-6} kg

- The force exerted on the web is the weight of the fly, so:

F=mg=(15\cdot 10^{-6}kg)(9.81 m/s^2)=1.47\cdot 10^{-4}N

- The stretching of the web is

x=4.0 mm=0.004 m

So if we solve eq.(1) for k, we find the spring constant:

k=\frac{F}{x}=\frac{1.47\cdot 10^{-4} N}{0.004 m}=0.037 N/m

3 0
3 years ago
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