Answer:
a,b,c,d,,f, g, j
Explanation:
e) equipotential lines are lines connecting points of equal potential
h) electric field inside the conductor is non-zero even when there is net movement of charge or non-zero current.
i) capacitors' plates are charged and an electric field exists between the plates.
Answer:
The speed of the vehicles immediately after the collision is 5.84 m/s.
Explanation:
The speed of the vehicles after the collision can be found by conservation of linear momentum:


Where:
m₁: is the mass of the car = 0.5 ton = 500 kg
m₂: is the mass of the lorry = 9.5 ton = 9500 kg
: is the initial speed of the car = 40 km/h = 11.11 m/s
: is the initial speed of the lorry = 20 km/h = 5.56 m/s
: is the final speed of the car =?
: is the final speed of the lorry =?
Since the two vehicles become tightly locked together after the collision
=
:


Therefore, the speed of the vehicles immediately after the collision is 5.84 m/s.
I hope it helps you!
I think if I was a researcher I would review my work or the sources I use, True
I believe this question ask for the energy dissipated by
friction.
The overall energy equation for this is:
F = PE – KE
where F is friction loss, PE is potential energy = m g h,
KE is kinetic energy = 0.5 m v^2
<span>F = 66 kg * 9.8 m/s^2 * 170 m – 0.5 * 66 kg * (11 m/s)^2</span>
<span>F = 105,963 J ~ 106,000 J </span>