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KIM [24]
1 year ago
15

Calculate the mean kinetic energy {e1rans) in joules of the following molecules at 350 k: (a) he, (b) co2, and (c) uf6. explain

your results.
Chemistry
1 answer:
Lady bird [3.3K]1 year ago
4 0

The mean kinetic energy per molecule is , where  is the Boltzmann constant and T is the absolute temperature.

So at 1000°C, the T = 1273.15 K, kB=1.38 × 10-23, therefore the mean kinetic energy is 2.635 × 10⁻²⁰J.

<h3><u>What is Kinetic energy ?</u></h3>

The energy an item has as a result of motion is known as kinetic energy.

A force must be applied to an item in order to accelerate it. We must put forth effort in order to apply a force. After the job is finished, energy is transferred to the item, which then moves at a new, constant speed. Kinetic energy is the type of energy that is transmitted and is dependent on the mass and speed attained.

Kinetic energy may be converted into other types of energy and transported between things. A flying squirrel may run into a chipmunk that is standing still, for instance. Some of the squirrel's original kinetic energy may have been transferred to the chipmunk or changed into another kind of energy after the impact.

To view more about kinetic energy, refer to;

brainly.com/question/2972267

#SPJ4

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How is the accuracy of the oxygen determination affected by the addition of a gas into the stream that is reduced by a reaction
Ede4ka [16]

Answer:

Decreased because the method can not distinguish oxygen from the gas added

Explanation:

6 0
3 years ago
Warm Up: Compete this conversion. Put just the number below *
Gwar [14]

Answer:

4 1/2

Explanation:

Use a ratio to find your answer

 4          6

-----  =  -------

 3           x

Cross multiply to solve for x.

4x = 18

x = 18/4

x = 4 2/4  which is the same as 4 1/2

5 0
2 years ago
each year, one person in north america uses resources equal to how much land? A. 12 miles B. 12 acres C. 120 acres
KATRIN_1 [288]
B. 12 acres

i think i don’t do geography
4 0
3 years ago
A nuclear power plant operates at 40.0% efficiency with a continuous production of 1042 MW of usable power in 1.00 year and cons
Sergio039 [100]

Answer:

3.00 x 10^-11 joules / atom of U-235

Explanation:

We know that the formula for Power = Work done (w)/Time (t)

We need to get the joules from power , since Joules is the SI unit of work.

From the formula P = W/t

W = Power (P) * Time (t)

The SI unit for Time is seconds, hence we change 1 year in seconds

1yr * 365 days/yr * 24hrs/day * 60mins/hr * 60 secs/min = 31536000 secs

It was stated in the question that the plant operates at an efficiency of 40%,

Thus to get the true power we divide the power provided in the question by 0.4 or 40%

= X(0.4) = 1042MW

True Power X = 1042/0.4 = 2605MW

Thus true power = 2605 * 10^6 Watts

Now we have the time in seconds and true power in Watts, we then find the work done.

From our above formula P = W/t

W = P*t = (2605* 10^6) (31536000) =

Finally, we can solve for our energy (work):

P = W / T        PT = W = (2880x10^6) (31536000) = 8.22 x 10^16 joules

We then calculate the amount of energy released by only 1 single uranium-235 atom.

= 8.22 x 10^16 joules / 1.07x10^6 g U-235 (235 g / 1 mol)(1 mol/6.0210^23 atoms)

= 3.00 x 10^-11 joules / atom of U-235

5 0
3 years ago
Consider the first-order reaction shown here. the yellow spheres in the pictures to the right represent the reactant,
Luda [366]
The rate constant of the reaction K we can get it from this formula:

K=㏑2/ t1/2 and when we have this given (missing in question):
that we have one jar is labeled t = 0 S and has 16 yellow spheres inside and the jar beside it labeled t= 10 and has 8 yellow spheres and 8 blue spheres and the yellow spheres represent the reactants A and the blue represent the products B

So when after 10 s  and we were having 16 yellow spheres as reactants and becomes 8 yellow and 8 blue spheres as products so it decays to the half amount so we can consider T1/2 = 10 s
a) by substitution in K formula:
∴ K = ㏑2 / 10 = 0.069 
The amount of A (the reactants) after N half lives = Ao / 2^n
b) so no.of yellow spheres after 20 s (2 half-lives) =  16/2^2 = 4
and the blue spheres = Ao - no.of yellow spheres left = 16 - 4 = 12
c) The no.of yellow spheres after 30 s (3 half-lives) = 16/2^3 = 2
and the blue spheres = 16 - 2 = 14

8 0
3 years ago
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