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Fofino [41]
3 years ago
8

.25 g of each of the following gasses are taken at 27°C and 600 mm

Chemistry
1 answer:
horsena [70]3 years ago
6 0

HI has the least volume

<h3>Further explanation</h3>

Given

Gasses and molar mass

Required

The least volume

Solution

Ideal gas law

PV=nRT

V = (nRT)/P

n = mass : MW(Molar weight=molar mass)

\tt V=\dfrac{\dfrac{mass}{MW}RT }{P}\\\\V=\dfrac{mass.RT}{MW.P}

<em>so V is inversely proportional to MW(molar mass)</em>

Because the values of P, R, T, and mass are the same, what matters is the value of the molar mass of each compound. The larger the molar mass the smaller the volume

From the available molar mass data, HI has the largest molar mass, so HI has the smallest volume

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Predict the sign of the entropy change, ΔS∘, for each of the reaction displayed.Drag the appropriate items to their respective b
Sonja [21]

Answer:

Ag+(aq)+Br−(aq)→AgBr(s)                                NEGATIVE

CaCO3(s)→CaO(s)+CO2(g)2                           POSITIVE

NH3(g)→N2(g)+3H2(g)                                    POSITIVE

2Na(s)+Cl2(g)→2NaCl(s)                                 NEGATIVE

C3H8(g)+5O2(g)→3CO2(g) +4H2O(g)           POSITIVE

I2(s)→I2(g)                                                        POSITIVE

Explanation:

We have to remember, to solve this problem, that the entropy of a gas is higher than that of a liquid which in turn  is higher than the solid. Therefore, comparing the reactants and products look for changes in the state of reactants and products. We also have to look for the increase or decrease of moles of each state based on the balanced chemical reaction.

Ag+(aq)+Br−(aq)→AgBr(s)

The reaction product is a single solid and the  the reactants were 2 species in solution. The change in entropy is negative.

CaCO3(s)→CaO(s)+CO2(g)2

Here we have a solid reactant and we have a solid product plus a gas product. The change in entropy is positive.

NH3(g)→N2(g)+3H2(g)

We have 4 mole gases as products starting from 1 mol reactant gas, the entropy has increased.

2Na(s)+Cl2(g)→2NaCl(s)

In this reaction 2 mol solid Na and 1 mol Cl₂ gas are converted into 2 mol solid NaCl, the entropy has decreased.

C3H8(g)+5O2(g)→3CO2(g) +4H2O(g)

The products are 7 mol of gas versus 6 mol of gas reactants and therefore entropy has increased.

I2(s)→I2(g)

1 mol solid I₂ goes into 1 mol gas making the change in  the entropy higher.

4 0
3 years ago
When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II)
katen-ka-za [31]

Answer:

3.81 g Pb

Explanation:

When a lead acid car battery is recharged, the following half-reactions take place:

Cathode: PbSO₄(s) + H⁺ (aq) + 2e⁻ → Pb(s) + HSO₄⁻(aq)  

Anode: PbSO₄(s) + 2 H₂O(l) → PbO₂(s) + HSO₄⁻(aq) + 3H⁺ (aq) + 2e⁻

We can establish the following relations:

  • 1 A = 1 c/s
  • 1 mole of Pb(s) is deposited when 2 moles of e⁻ circulate.
  • The molar mass of Pb is 207.2 g/mol
  • 1 mol of e⁻ has a charge of 96468 c (Faraday's constant)

Suppose a current of 96.0A is fed into a car battery for 37.0 seconds. The mass of lead deposited is:

37.0s.\frac{96.0c}{s} .\frac{1mole^{-} }{96468c} .\frac{1molPb}{2mole^{-} } .\frac{207.2gPb}{1molPb} =3.81gPb

6 0
3 years ago
The freezing point of water in degrees Celsius is [ Select ] __________. The freezing point of water in degrees Fahrenheit is [
ElenaW [278]

Answer: 0, 32 , 273

Explanation:

The freezing point of water in degree Celsius, Fahrenheit and Kelvin are in the following order;   0  , 32  , 273

4 0
3 years ago
Which is the most important factor in determining the state of a substance?
Contact [7]
Temperature, that's the most important factor
3 0
3 years ago
What is the wavelength of a photon with an energy of 3.38 x 10-19 J?
irina1246 [14]

Answer:

C. 588 nm

Explanation:

Given parameters:

Energy of the photon  = 3.38 x 10⁻¹⁹J

Unknown:

Wavelength of the photon   = ?

Solution:

The energy of a photon can be expressed as;

     E = \frac{hc}{wavelength}

    hc  = E x wavelength

     Wavelength  = \frac{hc }{E}  

  h is the Planck's constant = 6.63 x 10⁻³⁴m²kg/s

  c is the speed of light  = 3 x 10⁸m/s

  E is the energy  

   Wavelength = \frac{6.63 x 10^{-34} x 3 x 10^{8} }{3.38 x 10^{-19} }    = 5.89 x 10⁻⁷m

4 0
3 years ago
Read 2 more answers
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