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2 years ago

.25 g of each of the following gasses are taken at 27°C and 600 mm

Chemistry

1 answer:

horsena [70]2 years ago

6 0

HI has the least volume

<h3>Further explanation</h3>

Given

Gasses and molar mass

Required

The least volume

Solution

Ideal gas law

PV=nRT

V = (nRT)/P

n = mass : MW(Molar weight=molar mass)

$\tt V=\dfrac{\dfrac{mass}{MW}RT }{P}\\\\V=\dfrac{mass.RT}{MW.P}$

<em>so V is inversely proportional to MW(molar mass)</em>

Because the values of P, R, T, and mass are the same, what matters is the value of the molar mass of each compound. The larger the molar mass the smaller the volume

From the available molar mass data, HI has the largest molar mass, so HI has the smallest volume

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Hybridisation influences the bond length and bond enthalpy strength in organic compounds. The sp hybrid orbital contains more s character and hence it is closer to its nucleus and forms shorter and stronger bonds than the sp3 hybrid orbital.

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3 years ago

1. Matter can be measured in many ways for specific purposes. Which measurement depends on the force of gravity it is not reliab

Ganezh [65]

Answer:

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Explanation:

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3 years ago

A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration o

taurus [48]

Answer:

The concentration the student should write down in her lab is 2.2 mol/L

Explanation:

Atomic mass of the elements are:

Na: 22.989 u

S: 32.065 u

O: 15.999 u

Molar mass of sodium thiosulfate, Na2S2O3 = (2*22.989 + 2*32.065 + 3*15.999) g/mol = 158.105 g/mol.

Mass of Na2S2O3 taken = (19.440 - 2.2) g = 17.240 g.

For mole(s) of Na2S2O3 = (mass taken)/(molar mass)

= (17.240 g)/(158.105 g/mol) = 0.1090 mole.

Volume of the solution = 50.29 mL = (50.29 mL)*(1 L)/(1000 mL)

= 0.05029 L.

To find the molar concentration of the sodium thiosulfate solution prepared we use the formula:

= (moles of sodium thiosulfate)/(volume of solution in L)

= (0.1090 mole)/(0.05029 L)

= 2.1674 mol/L

6 0

3 years ago

How many grams of sodium phosphate are formed by the reaction of 10 g of sodium with phosphoric acid?

Norma-Jean [14]

Answer:

23.8g of sodium phosphate are formed

Explanation:

Based on the reaction of sodium, Na, with phosphoric acid, H₃PO₄:

3Na + H₃PO₄ → Na₃PO₄ + 3/2 H₂

<em>3 moles of sodium produce 1 mole of sodium phosphate</em>

<em />

To solve this question we must find the moles of sodium in 10g. Using the chemical reaction we can find the moles -And the mass- of sodium phosphate produced, as follows:

<em>Moles Na -Molar mass: 22.99g/mol-</em>

10g * (1mol / 22.99g) = 0.435 moles Na

<em>Moles Na₃PO₄:</em>

0.435 moles Na * (1mol Na₃PO₄ / 3mol Na) = 0.145 moles Na₃PO₄

<em>Mass Na₃PO₄ -Molar mass: 163.94g/mol-</em>

0.145 moles Na₃PO₄ * (163.94g/mol) =

<h3>23.8g of sodium phosphate are formed</h3>

8 0

2 years ago

A chemistry student needs 10.00 g of isopropenylbenzene for an experiment. He has available 120. g of a 42.7% w/w solution of is

Vanyuwa [196]

<u>Answer:</u> The mass of solution that the chemistry student should use is 23.4 grams

<u>Explanation:</u>

We are given:

Available mass of isopropenylbenzene = 120. g

Amount of isopropenylbenzene needed by chemistry student = 10.00 g

42.7 % (w/w) solution of isopropenylbenzene.

This means that 42.7 grams of isopropenylbenzene is present in 100 grams of solution.

To calculate the mass of solution for given needed of isopropenylbenzene, we apply unitary method:

For 42.7 grams of isopropenylbenzene, the amount of solution needed is 100 grams

So, for 10.00 grams of isopropenylbenzene, the amount of solution needed will be = $\frac{100}{42.7}\times 10=23.4g$

Hence, the mass of solution that the chemistry student should use is 23.4 grams

3 0

3 years ago