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blondinia [14]
2 years ago
7

Sulphur burnt in oxygen forms sulphur dioxide. Calculate the heat given out when 1.6g of sulphur is burnt.

Chemistry
1 answer:
adell [148]2 years ago
4 0

Answer:

Dont know

Explanation:

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You've probably heard that some types of bacteria can cause infections and make you sick.
Novosadov [1.4K]

Answer:

<u>(A) Plants would probably not have enough nitrogen.</u>

Explanation:

<em>According to the passage, bacteria help us digest our food and make yogurt. But it is the bacteria in the soil specifically that "Cycle nitrogen through the ecosystem, which plants rely on"</em>

6 0
2 years ago
Explain the similarities and differences between putting a beaker of ethanoic acid in the refrigerator and mixing it with sodium
frez [133]

Answer:

See explanation

Explanation:

When a beaker of ethanoic acid is placed in the refrigerator, its temperature drops and the vessel feels cool.

Now, when we mix ethanoic acid and sodium carbonate, an endothermic reaction occurs, fizzing is observed as carbon dioxide is given off and heat is lost to the surroundings causing the reaction vessel to feel cool to touch.

The difference between putting ethanoic acid in the refrigerator and adding  sodium carbonate to the solution is that, in the former, no new substance is formed. The substance remains ethanoic acid when retrieved from the refrigerator. In the later case, new substances are formed. The substance is no more ethanoic acid because a chemical reaction has taken place.

5 0
3 years ago
For the balanced equation shown below, what would be the limiting reagent if 93.9grams
svlad2 [7]

Answer: A. C2H3F

Explanation:

5 0
2 years ago
A 7.27-gram sample of a compound is dissolved in 250. grams of benzene. The freezing point of this solution is 1.02°C below that
UkoKoshka [18]

Answer:

The correct answer is 146 g/mol

Explanation:

<em>Freezing point depression</em> is a colligative property related to the number of particles of solute dissolved in a solvent. It is given by:

ΔTf = Kf x m

Where ΔTf is the freezing point depression (in ºC), Kf is a constant for the solvent and m is the molality of solution. From the problem, we know the following data:

ΔTf = 1.02ºC

Kf = 5.12ºC/m

From this, we can calculate the molality:

m = ΔTf/Kf = 1.02ºC/(5.12ºC/m)= 0.199 m

The molality of a solution is defined as the moles of solute per kg of solvent. Thus, we can multiply the molality by the mass of solvent in kg (250 g= 0.25 kg) to obtain the moles of solute:

0.199 mol/kg benzene x 0.25 kg = 0.0498 moles solute

There are 0.0498 moles of solute dissolved in the solution. To calculate the molar mass of the solute, we divide the mass (7.27 g) into the moles:

molar mass = mass/mol = 7.27 g/(0.0498 mol) = 145.9 g/mol ≅ 146 g/mol

<em>Therefore, the molar mass of the compound is 146 g/mol </em>

6 0
3 years ago
The solubility of potassium sulfate in water is 16 grams per 100
kicyunya [14]

The answer is 25 grams for this question

7 0
3 years ago
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