Answer:
A single compound is simultaneously oxidized and reduced.
Explanation:
In chemistry, disproportionation is a simultaneous oxidation and reduction of a single chemical specie.
What this means is that; in a disproportionation reaction, only one compound is both oxidized and reduced. This implies that two products are formed during disproportionation. One is the oxidized product while the other is the reduced product.
Consider the disproportionation of CuCl shown below;
2CuCl -----> CuCl2 + Cu
Here, CuCl2 is the oxidized product while Cu is the reduced product.
Answer: 1.6L
Explanation:
V1 = 1.50 L,
V2 =?
n1 = 3mol
n2 = 3 + 0.2 = 3.2mol
From PV = nRT
V1 /n1 = V2/n2
1.5/3 = V2 /3.2
V2 = (1.5/3/) x 3.2 = 1.6L
B because acetic acid is a weak acid and large quantity means you make it become concentrated
Answer:
Explanation:
Hello there!
Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:
![K=\frac{[NO_2]^2}{[NO]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BNO%5D%5E2%5BO_2%5D%7D)
Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:
In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.
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Hoi!!
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