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3 years ago

Help pls algebra 2 asap

Mathematics

1 answer:

Snezhnost [94]3 years ago

5 0

Answer:

help is on the way

Step-by-step explanation:

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What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1,5)?

romanna [79]

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{5 - (-1)}{-1 - 3} = \frac{5 + 1}{-4} = \frac{6}{-4} = \frac{3}{-2} = -1\frac{1}{2}$
y - y₁ = m(x - x₁)
y - (-1) = -1¹/₂(x - 3)
y + 1 = -1¹/₂(x) + 1¹/₂(3)
y + 1 = -1¹/₂x + 4¹/₂
      - 1 - 1
   y = -1¹/₂x + 3¹/₂

4x + y - 2 = 0
      + 2 + 2
       4x + y = 2
4x - 4x + y = -4x + 2
   y = -4x + 2
   y - y₁ = m(x - x₁)
      y - (-3) = -4(x - 4)
       y + 3 = -4(x) + 4(4)
   y + 3 = -4x + 16
       - 3 - 3
   y = -4x + 13

2x - 3y - 5 = 0
       + 5 + 5
2x - 2x - 3y = -2x + 5
   -3y = -2x + 5
      -3    -3
      y = ²/₃x - 1²/₃
   y - (-3) = -1¹/₂(x - 4)
      y + 3 = -1¹/₂(x) + 1¹/₂(4)
      y + 3 = -1¹/₂x + 6
      - 3     - 3
      y = -1¹/₂x + 3

8 0

4 years ago

Read 2 more answers

The vertices of a figure are labeled clockwise A(–4, 2), B(2, 4), C(7, 1), and D(–5, –3). How could you show that the figure is

Sidana [21]

Plot the points on a graph and join them to form a closed figure. two sides that are parallel shows it is a trapezoid

4 0

3 years ago

Write the equations for all vertical horizontal asymptotes. Vertical asymptote(s):Horizontal asymptote(s):Find all x-intercepts

NISA [10]

We have the next graph

And we must find:

1. Vertical asymptote(s):

We can see that there is a vertical asymptote when x = 2.

So, the vertical asymptote is

$x=2$

2. Horizontal asymptote(s):

We can see that there is a horizontal asymptote y = -1

So, the horizontal aymptote is

$y=-1$

3. x-intercept(s) and y-intercept(s):

We can see the graph intercepts the x-axis when x = -6

So, the x-intercept is (-6, 0)

We can see the graph intercepts the y-axis when y = 3

So, the y-intercept is (0, 3)

4. Domain nd Range:

Domain: The domain is the set of numbers that we can take in x-axis for the function.

Since we have a vertical asymptote that is x = 2 and we don´t have any more vertical asymptote the domain will be all real numbers except the value of the asymptote. So, the domain is

$\text{domain}\colon(-\infty,2)\cup(2,\infty)$

Range: The range is the set of numbers that the function takes in the y-axis.

Since we have only one horizontal asymptote the range will be all reals numbers except the value of the horizontal asymptote. So, the range is

$\text{range}\colon(-\infty,-1)\cup(-1,\infty)$

7 0

1 year ago

A surveyor wishes to lay out a square region with each side having length

SSSSS [86.1K]

This would represent the perimeter or area of the square region.I believe the answer points to how much is the perimeter and area of the lay out region.
Thank you for your question. Please don't hesitate to ask in Brainly your queries.

6 0

3 years ago

Is 18-3(2p+4) -3p equivalent to 3(2-3p)

Murljashka [212]

Answer:

<u>Yes they are equivalent.</u>

Step-by-step explanation:

Use PEMDAS: Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction

Distribute or multiply -3 with 2p and 4 to get -6p and -12.

You will then have 18-6p-12-3p, simplify to get 6-9p

For the second equation multiply 3 with 2 and -3p, you will then get 6-9p as well.

They are equal, hope the helps ;)

4 0

3 years ago