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BartSMP [9]
3 years ago
5

Write 3 to 5 sentences about predicting the properties of acids and bases​

Chemistry
1 answer:
Nataly_w [17]3 years ago
8 0

Answer:

cause of the properties of their aqueous solutions. Those properties are outlined below:

Aqueous solutions of acids are electrolytes, meaning that they conduct an electrical current. Some acids are strong electrolytes because they ionize completely in water, yielding a great many ions. Other acids are weak electrolytes that exist primarily in a non-ionized form when dissolved in water.

Acids have a sour taste. Lemons, vinegar, and sour candies all contain acids.

Acids change the color of certain acid-base indicators. Two common indicators are litmus and phenolphthalein. Blue litmus turns red in the presence of an acid, while phenolphthalein turns colorless.

Acids react with active metals to yield hydrogen gas. Recall that an activity series is a list of metals in descending order of reactivity. Metals that are above hydrogen in the activity series will replace the hydrogen from an acid in a single-replacement reaction, as shown below:

text{Zn}(s)+text{H}_2text{SO}_4(aq)rightarrow text{ZnSO}_4(aq)+text{H}_2(g)

Acids react with bases to produce a salt compound and water. When equal moles of an acid and a base are combined, the acid is neutralized by the base. The products of this reaction are an ionic compound, which is labeled as a salt, and water.

[10/31, 6:00 PM] Jana Taher: Bases have properties that mostly contrast with those of acids.

Aqueous solutions of bases are also electrolytes. Bases can be either strong or weak, just as acids can.

Bases often have a bitter taste and are found in foods less frequently than acids. Many bases, like soaps, are slippery to the touch.

Bases also change the color of indicators. Litmus turns blue in the presence of a base while phenolphthalein turns pink.

Bases do not react with metals in the way that acids do.

Bases react with acids to produce a salt and water.

Please note that tasting chemicals and touching them are NOT good lab practices and should be avoided in other words, don’t do this at home.

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What did the Bohr model assume about the motion of electrons?
gavmur [86]

Answer:

A

Explanation:

Bohr proposed that an electron is found only in specific circular paths, or orbits, around the nucleus

7 0
3 years ago
A chemist dilutes a 1.0 ml sample of 2.0 m kno3 by adding water to it. if the concentration of the solution that is obtained is
Nitella [24]

A chemist dilutes a 1.0 ml sample of 2.0M KNO₃ by adding water to it. If the concentration of the solution that is obtained is 0.0080 m, then its volume is 250mL.

<h3>How do we calculate volume?</h3>

Volume for the given equation will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

M₁ = molarity of KNO₃ = 2M

V₁ = volume of KNO₃ = 1mL

M₂ = molarity of final solution = 0.0080M

V₂ = volume of final solution = ?

On putting these values on the above equation, we get

V₂ = (2)(1) / (0.0080) = 250mL

Hence option (2) is correct.

To know more about molarity, visit the below link:

brainly.com/question/24305514

8 0
2 years ago
What is the overall reaction order for this rate law: rate = k[A]2[B][C]?
Kay [80]

Explanation:

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7 0
3 years ago
A 29.05 gram sample of cobalt is heated in the presence of excess oxygen. A metal oxide is formed with a mass of 40.88 g. Determ
deff fn [24]

The empirical formula of the oxide is Co₂O₃.

<em>Step 1</em>. Calculate the <em>mass of oxygen</em>

Your reaction is

 Cobalt + oxygen ⟶ cobalt oxide

29.05 g +    x g    ⟶     40.88 g

According to the <em>Law of Conservation of Mass</em>, the total mass of the reactants must equal the total mass of the products. Thus,

29.05 g + <em>x</em> g ⟶ 40.88 g

<em>x</em> = 40.88 – 29.05 = 11.83

<em>Step 2</em>. Calculate the <em>moles of each element</em>

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Co to O.

<em>Moles of Co</em> = 29.05 g Co × (1 mol Co /(58.93 g Co) = 0.492 96 mol Co

<em>Moles of </em>O = 11.83 g O × (1 mol O/16.00 g O) = 0.739 38 mol O

<em>Step 3</em>. Calculate the <em>molar ratio</em> of the elements

Divide each number by the smaller number of moles

Co:O = 0.429 26:0.739 38 = 1:1.4999

<em>Step 4</em>. Multiply each number by a factor that makes the <em>ratio close to whole numbers </em>

Multiply by 2. Then

Co:O = 2:2.998 ≈ 2:3

<em>Step 5</em>: Write the <em>empirical formula</em>

EF = Co₂O₃

4 0
3 years ago
A student dilutes 50.0 mL of a 0.10 mol/L to 0.010 mol/L. Which statement is true?​
VLD [36.1K]
The total amount of solute decreases.
6 0
3 years ago
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