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2 years ago

The reaction

Chemistry

1 answer:

Aliun [14]2 years ago

7 0

From he calculations, we can see that the total pressure at equilibrium is 21 atm.

<h3>What is equilibrium constant?</h3>

The term equilibrium constant commonly describes the constant that that shows the extent of conversion of reactants to products.

We have to find the pressure of each gas as follows;

For H2

P = nRT/V = 4.553 /2 × 0.082 × 1000/8.89 L = 21 atm

Using the ICE table;

C(s) + 2H2(g) ⇌ CH4(g)

I 21 atm 0

C -x +x

E 21 - x x

0.263= x/(21 - x )^2

0.263(21 - x )^2 = x

38 - 11x - 0.263x^2 = x

0.263x^2 + 12x - 38 = 0

x=2.97 atm

At equilibrium, we have;

(21 - 2.97) + 2.97 = 21 atm

Learn more about equilibrium constant: brainly.com/question/17960050

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Be sure to answer all parts. Consider the following balanced redox reaction (do not include state of matter in your answers): 2C

timurjin [86]

Answer:

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The specie which is reduced is:- $ClO^-$

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

$X^{n+}+ne^-\rightarrow X$

For the given chemical reaction:

$2CrO_2^- + 6ClO^- + 2H_2O\rightarrow 2CrO_4^{2-} + 3Cl_2 + 4OH^-$

The half cell reactions for the above reaction follows:

Oxidation half reaction: $CrO_2^- + 2H_2O + 4OH^-\rightarrow CrO_4^{2-} + 4H_2O + 3e^-$

Reduction half reaction: $2ClO^- + 4H_2O + 2e^-\rightarrow Cl_2 + 2H_2O + 4OH^-$

Thus, the specie which is oxidized is:- $CrO_2^-$

The specie which is reduced is:- $ClO^-$

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How many grams are in 6.00 moles of NaCl?

Anastasy [175]

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Alex17521 [72]

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