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3 years ago

Write a small paragraph on how to determine the speed of sound using the time of flight method.

Physics

1 answer:

Makovka662 [10]3 years ago

6 0

Answer:

time of flight of a pulse, and these most often

involve triggering of the measuring oscilloscope

with the signal that generates the sound pulse and

timing the time delay of the pulse picked up by a

conveniently placed microphone45

. Loren Winters

has reported a method similar in principle to the

present one, but which uses a completely different

detection system6

Explanation:

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A particle is moving along a circular path of 2-m radius such that its position as a function of time is given by u = (5t 2) rad

OverLord2011 [107]

Answer:

Explanation:

Given

radius of path $r=2\ m$

Velocity of Particle $\theta =5t^2 rad$

where t=time in seconds

angular velocity of particle is given by

$\omega =\frac{\mathrm{d} \theta }{\mathrm{d} t}$

$\omega =2\times 5t=10\cdot t$

And angular acceleration is given by

$\alpha =\frac{\mathrm{d} \omega }{\mathrm{d} t}$

$\alpha =10 rad/s^2$

tangential acceleration is $a_t=\alpha \times r$

$a_t=10\times 2=20\ m/s^2$

Centripetal acceleration $a_c=\omega ^2\times r$

$a_c=(10t)^2\times 2=200t^2$

net acceleration is sum of tangential and centripetal force at any time t is given by

$a_{net}=\sqrt{(a_c)^2+(a_t)^2}$

$a_{net}=\sqrt{(200t)^2+(20)^2}$

$a_{net}=20\sqrt{(10t)^2+1}\ m/s$

8 0

3 years ago

the impact time for a particular collision is 3.0 × 10-3 seconds and the impulse in the collision is 0.30 newton seconds. what i

Zanzabum

There are several information's already given in the question. The answer can be easily deduced using those information's.

Time = 3.0 * 10-3 seconds
Impulse = 0.30 newton
Then
Force = Impulse/Time
= 0.30/3.0 * 10-3
= 1 * 10^3 newtons.
I hope the above procedure is clear for you to understand and it has actually come to your great help.

3 0

4 years ago

The stoplight had just changed and a 2200 kg cadillac had entered the intersection, heading north at 2.8 m/s , when it was struc

tekilochka [14]

<span>3. The attempt at a solution So basically what I did was divided into components. x: (3)(2000) = (3000)*v_x y: (v_vw)*(10000) = (3000)*v_y v_x, v_y is the velocity (after collision) in the x and y direction, respectively, of both cars stuck together (since it is an inelastic collision). v_vw is the initial velocity of the Volkswagen. Now what I did was that the angle is 35 degrees north of east. So basically made a triangle and figured that tan(35) = (v_y)/(v_x). This means (v_x)*(tan35) = v_y. Then, I simplified the component equations to get: x: 2 = v_x y: v_vw = 3*v_y Then plugging in for v_y, I got: v_vw = 3(2)(tan35) = 4.2 m/s as the velocity of the volkswagen. However, the answer key says 8.6 m/s. Could someone please help me out? Thanks Phys.org - latest science and technology news stories on Phys.org â€˘ Game over? Computer beats human champ in ancient Chinese game â€˘ Simplifying solar cells with a new mix of materials â€˘ Imaged 'jets' reveal cerium's post-shock inner strength Oct 24, 2012 #2 ehild Homework Helper Gold Member What directions you call x and y? Reference https://www.physicsforums.com/threads/2d-momentum-problem.646613/</span>

7 0

3 years ago

A car travels at a constant speed of 15 m/s for 2 minutes. The car increases its speed from 15 m/s to 25 m/s during the next min

Rzqust [24]

Answer:

Graph F.

Explanation:

From the question given above, the following information were obtained:

1. The car travelled at a constant speed of 15 m/s for 2 minutes. This implies that the car is already moving and the graph can not be drawn from the origin.

Therefore, graph G is wrong.

2. The car increases its speed from 15 m/s to 25 m/s during the next minute and travels at a constant speed of 25 m/s for 2 more minutes.

This implies that the graph of the motion will project upward.

Therefore, graph H and J are wrong.

From the illustrations above, graph F gives the correct discription for the motion of the car.

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3 years ago

What is the relationship between power and voltage

FrozenT [24]

Answer

Voltage is how fast the electrons flow. Power is a use of voltage times the volumes of electrons. The higher the voltage the more power you have with the same current.

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3 years ago