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laiz [17]
2 years ago
9

During the deceleration of an ascending elevator, the normal force on the feet of a passenger is _____ her weight. During the de

celeration of a descending elevator, the normal force on the feet of a passenger is _____ her weight.
Physics
1 answer:
gizmo_the_mogwai [7]2 years ago
7 0

Answer: Smaller than ; larger than

Explanation:

When the elevator is moving in the upward direction, then the force acting on it is negative in nature because of

N= mg +ma, (g is gravity and a is acceleration)

here ma is negative so the N= mg-ma

Hence, it feels smaller than its original weight.

When the elevator is moving downward , then the force acting will be positive in nature

N= mg+ma,

here ma will be positive so it feels larger the original weight of passenger.

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How many atoms of Carbon (C) are in 3CO2
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in co2 there is one atom of carbon

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Which choice most accurately defines resistance and voltage of a circuit?
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c

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2 years ago
A 2.00-kg rock has a horizontal velocity of magnitude 12.0 m>s when it is at point P in Fig. E10.35. (a) At this instant, wha
zaharov [31]

Answer:

(A) L = 115.3kgm²/s

(B) dL/dt = 94.1kgm²/s²

Explanation:

The magnitude of the angular momentum of the rock is given by the foemula

L = mvrSinθ

We have been given θ = 36.9°, m = 2.0kg, v = 12.0m/s and r = 8.0m.

Therefore L = 2.00 × 12 × 8.0 × Sin 36.9° =

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7 0
2 years ago
A spool of thread has an average radius of 1.00 cm. If the spool contains 62.8 m of thread, how many turns of thread are on the
Simora [160]

To solve this problem we will start from the given concept in which the number of turns is equivalent to the length of the thread per circumference of spool. That is:

N = \frac{l}{\phi}

Where,

l = length of the thread

\phi= circumference of spool

For \phi we have that,

\phi = 2\pi r \rightarrow 2\pi (0.01)

For l  we have that

l = 62.8m

Finally the number of Turns would be,

N = \frac{l}{\phi}

N = \frac{62.8}{2\pi (0.01)}

N = 1000turns

Therefore the number of turns of thread on the spool are 1000turns.

7 0
3 years ago
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