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3 years ago

The width of a rectangle is 2 less than twice the length, x. If the perimeter is 44, what is the width?

Mathematics

1 answer:

Butoxors [25]3 years ago

3 0

Take the length as 'x'

Width = 2x - 2

Perimeter = 44 [ Formula = 2(l + w) ]

2 (l + w) = 44

2 (x + 2x - 2) = 44

2 (3x - 2) = 44

6x - 4 = 44

6x = 44 + 4

6x = 48

x = 48/6

x = 8 => length

Width = 2x - 2 = 2(8) - 2 = 14 units.

Hope it helps!

꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂

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densk [106]

Not really well frased question. im guessing you mean the hypotonouse is 61 and the height is 11. you can use the pythagorean theorem by doing a squared plus b squared equals c squared. you know 2 variables, a and c. so you can do 11 squared plus b squared equals 61 squared. so 121 plus b squared equals 3721. then 3721-121 is 3600. the square root of 3600 is 60, giving 60 as the answer.

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3 years ago

Can help me understand this?

Tanzania [10]

Answer:

Its easy just fill in the blacks

Step-by-step explanation:

P1 is 5 P2 is 2 P3 is 4 and so on now the odd and even u add the odd number together and the even together like 2+2+1 (the even side) =5 so put 5 in the even and do the same thing to odd 5+4+6 = 15 and put 15 on odd #

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3 years ago

" According to the Joy Cone Company, their waffle cones have a diameter of 2 5/8 inches and a

ASHA 777 [7]

Answer:

No, the cone will not hold all of the ice cream.

Step-by-step explanation:

Given:

" According to the Joy Cone Company, their waffle cones have a diameter of 2 5/8 inches and a height of 6 inches.

If you place one scoops of ice cream (in the shape of a sphere) with a diameter of 2 7/8 inches would let it melt.

Now, to explain mathematically will the cone hold all of the ice cream.

Taking the value of π = 3.14.

So, to get the volume of waffle cone we put formula:

Height (h) = 6 inches.

Diameter = $2\frac{5}{8}=\frac{21}{8}\ inches.$

Thus radius (r) = Diameter ÷ 2 = $\frac{\frac{21}{8}}{2} =\frac{21}{16} \ inches.$

$Volume=\pi r^2\frac{h}{3}$

$Volume=3.14\times \frac{21}{16} \times \frac{21}{16} \times \frac{6}{3}$

$Volume=3.14\times 1.31\times 1.31\times 2$

$Volume=10.78\ inches^3.$

The volume of waffle cone = 10.78 inches³.

Now, to get the volume of scoop which is in the shape of sphere we put formula:

Diameter = $2\frac{7}{8} =\frac{23}{8} \ inches.$

Thus radius (r) = Diameter ÷ 2 $=\frac{\frac{23}{8}}{2} =\frac{23}{16} \ inches.$

$Volume = \frac{4}{3} \pi r^3$

$Volume = \frac{4}{3} \times 3.14\times \frac{23}{16} \times \frac{23}{16} \times \frac{23}{16}$

$Volume=1.33\times 3.14\times 1.44\times 1.44\times 1.44$

$Volume=12.47\ inches^3.$

The volume of one scoop of ice cream = 12.47 inches³.

So, as the volume of scoop of ice cream is more than the volume of cone.

Thus, if placing one scoop of ice cream in the cone and let it melt, the cone will not hold all of the ice cream.

Therefore, no the cone will not hold all of the ice cream.

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This statement is true.

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The best intervals would be 41-45, 46-50, 51-55, 56-60, 61-65, and 69-70.

The best way to decide the appropriate interval would be to find the range of the numbers.

We have given a data set,

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The minimum is the smallest value in the data set. The maximum is the largest value in the data set.

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This would be 69-42=27.

If you need six intervals you would need to round 27 up to 30 to be able to divide it out evenly and include all of the data.

The best intervals would be 41-45, 46-50, 51-55, 56-60, 61-65, and 69-70.

This way you are one over and one under the highest and lowest values.

Therefore, The best intervals would be 41-45, 46-50, 51-55, 56-60, 61-65, and 69-70.

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