PH = -log[H₃O⁺]
= -log(<span>3.5×10</span>⁻⁴)
= 3.46
Hence the pH of the given agricultural product is 3.46 which means the product is acidic.
If the pH > 7, then the solution is basic.
If the pH < 7, then the solution is acidic.
If the pH = 7, then solution is neutral.
Answer:
Experiment
Explanation:
It would be hard to develop a procedure to test the hypothesis
The number of electrons present in the nonbonding π molecular orbital of the allyl anion is 4 electrons . 2 in the pi bond of the allyl ion and the other two will be present as a lone pair on the carbon atom.
<h3>What is a nonbonding π molecular orbital?</h3>
It is a type of orbital that does not affect the bond order or bond length and the bond order of the molecule and does not affect its energy too.
In allyl anion allyl anion occupies 4 pi electrons and ψ2 is the Highest Occupied Molecular Orbital whereas ψ3* is the Lowest Unoccupied Molecular Orbital
Therefore, the number of electrons present in the nonbonding π molecular orbital of the allyl anion is 4 electrons . 2 in the pi bond of the allyl ion and the other two will be present as a lone pair in on the carbon atom.
Learn more about nonbonding π molecular orbital, here :
brainly.com/question/28175150
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Salt!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
Explanation:
Ksp(BaSO4)=1.07×10−10
BaSO₄ → Ba²⁺ + SO₄²⁻
1.07×10⁻¹⁰ = ( Ba²⁺) × ( SO₄²⁻)
but Ba²⁺ = 1.3×10⁻² M
1.07×10⁻¹⁰ = 1.3×10⁻² M × ( SO₄²⁻)
( SO₄²⁻) = 1.07×10⁻¹⁰ / 1.3×10⁻² = 0.823 × 10⁻⁸ M
while Ksp(CaSO4)=7.10×10−5
CaSO₄ → Ca²⁺ + SO₄²⁻
7.10×10⁻⁵ = 2.0×10⁻² × ( SO₄²⁻)
( SO₄²⁻) = 7.10×10⁻⁵ / 2.0×10⁻² = 3.55 × 10⁻³ M
comparing the concentration of sulfate ions, Ba²⁺ cation will precipitate first because the Ba²⁺ requires 0.823 × 10⁻⁸ M sodium sulfate which less compared the about needed by CaSO₄