Answer:
Fricción.
Explicación:
Caminando con otro compañero al mismo tiempo y al mismo ritmo, el movimiento se produce debido a la fricción del suelo y la suela de los zapatos porque la fricción es la fuerza que ayuda en el movimiento de los objetos de un lugar a otro. Si no hay fricción entre el suelo y la suela de los zapatos, no podemos dar un paso por lo que podemos decir que la fricción nos mueve hacia adelante.
Answer:
See Below
Explanation:
Okay, I thinkkk what it is asking by what you summarzied for me issss:
They split the total time into four quarters. They then took (for the first quarter) the start time. Then when the first quarter ends and the second quarter starts is the "end" time.
They then subtract the start time of the second quarter from the end time of the first quarter.
I hope this helps, good luck! :D
Answer:
Total distance = 700 m
Displacement = 500 m
Explanation:
Notice that Jed travelled a total of 3 x 100 m = 300 m in the North direction, and 300 m + 100 m = 400 m in the East direction. Therefore the total distance he travelled is: 300 + 400 = 700 m.
But the actual displacement is given by the Pythagorean theorem as the hypotenuse of a right angle triangle of legs 300 m and 400 m:
displacement = 
Answer:
change of momentum does not depend on the mass of the cars, as the force and time are the same all vehicles have the same change of momentum
Explanation:
Let's look for the speed of the car
F = m a
a = F / m
We use kinematics to find lips
v = v₀ + a t
v = v₀ + (F / m) t
The moment is defined by
p = m v
The moment change
Δp = m v - m v₀
Let's replace the speeds in this equation
Δp = m (v₀
+ F / m t) - m v₀
Δp = m v₀ + F t - m v₀
Δp = F t
We see that the change of momentum does not depend on the mass of the cars, as the force and time are the same all vehicles have the same change of momentum
Answer:17.08 s
Explanation:
Given
distance between First and second Runner is 45.6 m
speed of first runner
=3.1 m/s
speed of second runner
=4.65 m/s
Distance between first runner and finish line is 250 m
Second runner need to run a distance of 250+45.6=295.6 m
Time required by second runner 
time required by first runner to reach finish line
Thus second runner reach the finish line 80.64-63.56=17.08 s earlier
