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elena55 [62]
3 years ago
9

Someone that understands this please help!ASAP it’s 8th grade math

Mathematics
2 answers:
Ivahew [28]3 years ago
5 0

Answer:

simple ( principal *rate*time)/100.

3500*4*10/100 = 1400 interest

account balance =3500+1400=4900

compound p(1+r)^t

3500(1+.04)^10 =3500* 1.480=5180

interest earned = 5180-3500= 1680

how much more interest. ; 1680-1400=280

Gekata [30.6K]3 years ago
4 0

Answer:

Step-by-step explanation:

<u><em>Simple Interest:</em></u>

Simple Interest formula is S.I. = P × r × t

<em>Interest Eared</em>: $3,500 × 0.04 × 10 = <em>$1,400</em>

Account Balance formula is A = P ( 1 + rt )

<em>Account Balance</em>: $3,500 + $1,400 = <em>$4,900</em>

<u><em>Compound Interest:</em></u>

Compound Interest formula: A =P(1+r)^{t}

Account balance: <em>$5,180.85</em>

Interest Earned: $5,180.85 - 3,500.00 = <em>$1,680.85</em>

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Maximize the objective function P = 2x + 1.5y for the feasible region shown. State the maximum value for P and the ordered pair
umka2103 [35]

Incomplete question. However, let's assume this are feasible regions to consider:

Points:

- (0, 100)

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Answer:

<u>Maximum value occurs at 325 at the point (0, 325)</u>

<u>Step-by-step explanation:</u>

Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.

- For point (0, 100): P= 2(0) + 1.5 (100) =150

- For point (0, 125): P= 2(0) + 1.5 (125) =187.5

For point (0, 325): P= 2(0) + 1.5 (325) = 487.5

For point (1, 200): P= 2(1) + 1.5 (200) = 302

Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.

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