The first step in the reaction is the double bond of the Alkene going after the H of HBr. This protonates the Alkene via Markovnikov's rule, and forms a carbocation. The stability of this carbocation dictates the rate of the reaction.
<span>So to solve your problem, protonate all your Alkenes following Markovnikov's rule, and then compare the relative stability of your resulting carbocations. Tertiary is more stable than secondary, so an Alkene that produces a tertiary carbocation reacts faster than an Alkene that produces a secondary carbocation.
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Explanation:
the quantity of energy that an isolated, gaseous atom in the ground electronic state must absorb to discharge an electron, resulting in a cation.
The shape of the sp3 orbitals is tetrahedral.
<h3>What are orbitals?</h3>
The term orbital refers to a region in space where there is a high probability of finding the electron. We know that sometimes orbitals could be combined in order to obtain the orbitals that are suited in energy to participate in chemical bonding. This is known as the hybridization of orbitals.
The sp3 orbital is a hybrid orbital The four hybrid orbitals are directed towards the corners of a regular tetrahedron. Hence the shape of the sp3 orbitals is tetrahedral.
Learn more about shapes of orbitals:brainly.com/question/11793076
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