Answer:
today, petroleum is mostly used as a source of energy, being rich in combustible carbon in the production of electricity or running some sorts of heat engines. ... Raw petroleum (also known as crude oil) is used in three major ways: Transportation, Electricity Generation, and Material Production.
Explanation:
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Answer:
The term organic chemistry originally meant the chemistry of compounds obtainable from plants and animals
Answer: The actual free-energy change for the reaction -8.64 kJ/mol.
Explanation:
The given reaction is as follows.
Fructose 1,6-bisphosphate 
Glyceraldehyde 3-phosphate + DHAP
For the given reaction, 
is 23.8 kJ/mol.
As we know that,
Here, R = 8.314 J/mol K, T = 
= (37 + 273) K
= 310.15 K
Fructose 1,6-bisphosphate = 
M
Glyceraldehyde 3-phosphate = 
M
DHAP = 
M
Expression for reaction quotient of this reaction is as follows.
Reaction quotient = ![\frac{[DHAP][\text{glyceraldehyde 3-phosphate}]}{[/text{Fructose 1,6-bisphosphate}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BDHAP%5D%5B%5Ctext%7Bglyceraldehyde%203-phosphate%7D%5D%7D%7B%5B%2Ftext%7BFructose%201%2C6-bisphosphate%7D%5D%7D)
Q = 
= 
Now, we will calculate the value of 
as follows.
= 
= -8647.73 J/mol
= -8.64 kJ/mol
Thus, we can conclude that the actual free-energy change for the reaction -8.64 kJ/mol.
Answer:
P2I4 is otherwise known as "<em>Diphosphorus Tetraiodide</em>"
Explanation:
The ionic strength of a solution, I, is defined as
I=1/2 Σ m_i z_i^2
Where m_i is the concentration of the ion, and z_i is the charge of the ion.
For 1 M NaCl solution, Ionic strength I = ½ (1*12 + 1*12) = 1.00;
For, 1 M (NH4)2SO4, concentration of [NH4] = 2 M and [SO4] = 1 M;
I = ½ (2*12 + 1*22) = 3.00;
so ionic strength of 1 M (NH4)2SO4 is different, therefore it is a serious error.
