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Olenka [21]
3 years ago
8

The number of carbon atoms in 45.21g C

Chemistry
1 answer:
Inga [223]3 years ago
7 0

Answer:

2.26 X10^24 carbon atoms

Explanation:

The number of carbon atoms in 45.21g C

carbon has an atomic mas of 12.01 gm

45.21 g  has 45.21/12.01 = 3.76 moles of C

a mole contains  Avogadros number of particles

6.022 X 10^23

3.76 moles contain 3.76 X6,022 X 10^23 =

2.26 X10^24 carbon atoms

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An ideal gas in a cylindrical container of radius r and height h is kept at constant pressure p. The bottom of the container is
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Answer:

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}  

Explanation:

The gas ideal law is  

PV= nRT (equation 1)

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P = pressure  

R = gas constant  

T = temperature  

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V = volume  

Working with equation 1 we can get  

n =\frac{PV}{RT}

The number of moles is mass (m) / molecular weight (mw). Replacing this value in the equation we get.

\frac{m}{mw} =\frac{PV}{RT}  or  

m =\frac{P*V*mw}{R*T}   (equation 2)

The cylindrical container has a constant pressure p  

The volume is the volume of a cylinder this is

V =(pi)*r^{2}*h

Where:

r = radius  

h = height  

(pi) = number pi (3.1415)

This cylinder has a radius, r and height, h so the volume is  V =(pi)*r^{2}*h

Since the temperatures has linear distribution, we can say that the temperature in the cylinder is the average between the temperature in the top and in the bottom of the cylinder. This is:  

T =\frac{T_{1} + T_{O}}{2}  

Replacing these values in the equation 2 we get:

m =\frac{P*V*mw}{R*T}   (equation 2)

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}    

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