Answer:
2.26 X10^24 carbon atoms
Explanation:
The number of carbon atoms in 45.21g C
carbon has an atomic mas of 12.01 gm
45.21 g has 45.21/12.01 = 3.76 moles of C
a mole contains Avogadros number of particles
6.022 X 10^23
3.76 moles contain 3.76 X6,022 X 10^23 =
u can just multiply 1
krkrfmfmmfdkd
9.0×10^23
1.5mols x =9.0×10^23
i = 7.58 × 10 to the -4 power
j = 4.573 × 10 to the sixth power
k = 3.438 × 10 to the -2 power
h = 5 × 10 to the third power
hope this helps!
Answer:The answer is C) The total mass of C and D only.