The arrow shows that the bond between the chlorine atom and the fluorine atom is nonpolar. The electrons in the bond are pulled more strongly by the fluorine atom, and the chlorine atom is slightly positive.
Explanation:
- The bond between Chlorine and fluorine is nonpolar bonding because both of them are sharing an equal number of electrons in the bond. H2, F2, and CL2 are common examples of this.
- Chlorine and fluorine are electronegative molecules but Fluorine is above chlorine in the periodic table. Since fluorine is above Chlorine, fluorine has slightly highest electronegative nature compare to fluorine. This is the reason why Fluorine molecules are attracting electrons more than chlorine atoms. This making chlorine atoms slightly positive in Cl and F bonding.
A b A or just the person above me said
Testable, that is always required for a hypothesis. Otherwise, how can you prove it?
Answer:
2.6×10^-19 J/photon
Explanation:
E of photon = h × ν
where h= 6.63 × 10^-34 j.s
v= C ÷ λ
E = ( h × c) ÷ λ
E = (6.63 × 10^-34 × 3.00
×10^8 ) ÷ ( 765 × 10^-9)
E = 2.6×10^-19 J/photon
