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Anastaziya [24]
3 years ago
12

If the energy emited is 2.3x10-15, what is the wavelength

Chemistry
1 answer:
spayn [35]3 years ago
8 0

Answer:

Explanation:

E=hf 2.3x10^-15 J=(6.63x10^-34 J/Hz)f

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Please Help Weak Acid Base Problems!!!
DiKsa [7]

Answer:

The procedure for calculating the pH of a solution of a weak base is similar to that of the weak acid in the sample problem. However, the variable x will represent the concentration of the hydroxide ion. The pH is found by taking the negative logarithm to get the pOH, followed by subtracting from 14 to get the pH.

Explanation:

3 0
3 years ago
Read 2 more answers
How many moles are there in 990 grams of sugar, C12H22011? (Sig Figs, do not
Nitella [24]

Answer:

Number of moles = 2.89 mol

Explanation:

Given data:

Number of moles of sugar  = ?

Mass of sugar = 990 g

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of C₁₂H₂₂O₁₁:

12× 12 + 22×1.008 + 16×11 = 342.2 g/mol

Number of moles = 990 g / 342.2 g/mol

Number of moles = 2.89 mol

6 0
3 years ago
4.
vova2212 [387]

Answer:

33.3gtts/min

Explanation:

We can find the drops/minute with common proportions.

100cc/1hr * 200gtts/1cc * 1hr/60min ≈ 33.3gtts/min

Best of Luck!

6 0
3 years ago
I really can’t do this don’t understand it
masya89 [10]

Answer:

7.96g, 33.79%

Explanation:

I'll try my best to explain the entire process behind this question ;)

From the question, you can write the reaction

2H_2O(l)->2H_2(g)+O_2(g)

Now, there are a few reasons it is like this. Oxygen is a diatomic element, meaning it doesn't and can't exist as just O. It exists as O₂. To balance, this, double the amount of water and hydrogen so there is an equal amount of  each element on both sides of the reaction (4 H's, 2 O's on the reactant side, and 4 H's, 2 O's on the product side).

From this we can get a mole-to-mole ratio.

Onto the stoichiometry. Our goal in this is to convert from grams of water to grams of hydrogen, and we do so with a mole to mole ratio.

71.0gH_2O*\frac{1molH_2O}{18.02g} *\frac{2molH_2}{2molH_2O}* \frac{2.02g}{1molH_2}\\\\ =7.96gH_2

Basically, what I did was divide by water's molar mass to get moles of water, multiplied by the mole-to-mole ratio (2:2) to get moles of H2, and then multiplied by H2's molar mass to get what should be the amount of H2 produced by the reaction.

For percent yield, you can calculate it is such:

\frac{Actual}{Theoretical}*100

Plug the numbers in:

\frac{2.69g}{7.96g}*100\\\\ =33.79%

So, the percent yield is 33.79%

3 0
3 years ago
How many grams of chlorine gas must react to give 3.52g of BiCl3 according to the equation in exercise 23?
marshall27 [118]
3.52g BiCl3 × 1 mol BiCl3/ 315.34g BiCl3 × 3 mol Cl/ 2 mol BiCl3 × 70.906g Cl/ 1 mol Cl= 1.187 g Cl
6 0
4 years ago
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