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3 years ago

In 1 to 2 sentences explain how you would determine the constant K for a spring

Physics

1 answer:

Olin [163]3 years ago

8 0

When spring times comes around you ever be like, "k." If you feel like that every year during spring then there you go

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You are an industrial engineer with a shipping company. As part of the package- handling system, a small box with mass 1.60 kg i

wlad13 [49]

Answer:

a) V = 0.82m/s

b) Vmax = 0.985 m/s

Explanation:

By conservation of energy we know that:

Eo = Ef $\frac{m*V^{2}}{2}-\frac{K*Xmax^{2}}{2}=-Ff*Xmax$

Solving for V we get:

V = 0.82 m/s

To find the maximum speed we will do the same to an intermediate point where the compression is X and the distance for the work donde by frictions is given by (Xmax - X) = (0.28m - X):

$\frac{m*Vmax^{2}}{2}+\frac{K*X^{2}}{2}-\frac{K*Xmax^{2}}{2}=-Ff*(Xmax-X)$

Then we have to solve for V, derive and equal zero in order to find position X. After solving the derivative we get:

X = 0.1m Replacing this value into the equation for Vmax:

Vmax = 0.985m/s

6 0

3 years ago

A pencil rolls horizontally of a 1 meter high desk and lands .25 meters from the base of the desk. How fast was the pencil rolli

vovikov84 [41]

Answer: 0.55 m/s

Explanation:

This situation is related to projectile motion (also called parabolic motion), where the main equations are as follows:

$x=V_{o} cos\theta t$ (1)

$y=y_{o}+Vo sin \theta t + \frac{g}{2}t^{2}$ (2)

Where:

$x=0.25 m$ is the horizontal displacement of the pencil

$V_{o}$ is the pencil's initial velocity

$\theta=0\°$ since we are told the pencil rolls horizontally before falling

$t$ is the time since the pencil falls until it hits the ground

$y_{o}=1 m$ is the initial height of the pencil

$y=0$ is the final height of the pencil (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity, always acting vertically downwards

Begining with (1):

$x=V_{o} cos(0\°) t$ (3)

$x=V_{o}t$ (4)

Finding $t$ from (2):

$0=1 m+ \frac{-9.8m/s^{2}}{2}t^{2}$ (5)

$t=\sqrt{\frac{-2y_{o}}{g}}$ (6)

Substituting (6) in (4):

$x=V_{o}\sqrt{\frac{-2y_{o}}{g}}$ (7)

Isolating $V_{o}$ :

$V_{o}=\frac{x}{\sqrt{\frac{-2y_{o}}{g}}}$ (8)

$V_{o}=\frac{0.25 m}{\sqrt{\frac{-2(1 m)}{-9.8m/s^{2}}}}$ (9)

Finally:

$V_{o}=0.55 m/s$

4 0

3 years ago

As your hand moves back and forth to generate longitudinal pulses in a spiral spring, your hand completes 3.19 back-and-forth cy

lesantik [10]

Explanation:

Since, it is given that one hand completes 3.19 vibrations in 8.46 sec. Therefore, in one second the number of vibrations will be as follows.

$\frac{3.19}{8.46}$

= 0.377 vibrations

Hence, frequency (f) = 0.38 Hz

Now, formula to calculate the speed is as follows.

v = $f \times \lambda$

or, $\lambda = \frac{v}{f}$

= $\frac{0.6 cm/s}{0.38}$

= 1.57 cm

Thus, we can conclude that the wavelength is 1.57 cm.

3 0

3 years ago

Please follow I will follow you

klio [65]

Answer:

aight

Explanation:

5 0

3 years ago

Read 2 more answers

How many electrons do hydrogeyn have?

zubka84 [21]

A hydrogen atom contains 1 electron, 1 proton, and no neutrons based on the Periodic Table. The isotopes of the hydrogen atoms however, do contain neutrons.

6 0

3 years ago