1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lisabon 2012 [21]
3 years ago
9

A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent

travelling waves CANNOT be:
Physics
1 answer:
azamat3 years ago
5 0

The wavelengths of the constituent travelling waves CANNOT be 400 cm.

The given parameters:

  • <em>Length of the string, L = 100 cm</em>

<em />

The wavelengths of the constituent travelling waves is calculated as follows;

L = \frac{n \lambda}{2} \\\\n\lambda = 2L\\\\\lambda = \frac{2L}{n}

for first mode: n = 1

\lambda = \frac{2\times 100 \ cm}{1} \\\\\lambda = 200 \ cm

for second mode: n = 2

\lambda = \frac{2L}{2} = L = 100 \ cm

For the third mode: n = 3

\lambda = \frac{2L}{3} \\\\\lambda = \frac{2 \times 100}{3} = 67 \ cm

For fourth mode: n = 4

\lambda = \frac{2L}{4} \\\\\lambda = \frac{2 \times 100}{4} = 50  \ cm

Thus, we can conclude that, the wavelengths of the constituent travelling waves CANNOT be 400 cm.

The complete question is below:

A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent travelling waves CANNOT be:

A. 400 cm

B. 200 cm

C. 100 cm

D. 67 cm

E. 50 cm

Learn more about wavelengths of travelling waves here: brainly.com/question/19249186

You might be interested in
A woman stands on a scale in a moving elevator. Her mass is 61.0 kg, and the combined mass of the elevator and scale is an addit
vazorg [7]
First, we need to find the acceleration
F = ma
9850 N = (815 kg + 61 kg)a
a = 11.24

the read of the scale during the acceleration is :


mg + ma

= (61 kg x 9.8) +  (61 kg x 11.24)
= 1283.4 N

hope this helps
 
7 0
4 years ago
Question 13 (1 point)
Leviafan [203]

Answer:

papa's donuteria

Explanation:

:rawr:

8 0
3 years ago
 I NEED TO KNOW FAST PLZ SOMEONE KNOW THE ANSWER Spiral galaxies usually contain many young stars, so they often have a reddish
spayn [35]
False. They often have a bluish tint.
6 0
4 years ago
A projectile of mass 2.0 kg is fired in the air at an angle of 40.0 ° to the horizon at a speed of 50.0 m/s. At the highest poin
tekilochka [14]

Answer:

a) The fragment speeds of 0.3 kg is 33.3 m / s on the y axis

                                         0.7 kg is 109.4 ms on the x axis

b)  Y = 109.3 m

Explanation:

This is a moment and projectile launch exercise.

a) Let's start by finding the initial velocity of the projectile

       sin 40 = voy / v₀

       v_{oy} = v₀ sin 40

       v_{oy} = 50.0 sin40

       v_{oy} = 32.14 m / s

       cos 40 = v₀ₓ / V₀

       v₀ₓ = v₀ cos 40

       v₀ₓ = 50.0 cos 40

       v₀ₓ = 38.3 m / s

Let us define the system as the projectile formed t all fragments, for this system the moment is conserved in each axis

Let's write the amounts

Initial mass of the projectile M = 2.0 kg

Fragment mass 1 m₁ = 1.0 kg and its velocity is vₓ = 0 and v_{y} = -10.0 m / s

Fragment mass 2 m₂ = 0.7 kg moves in the x direction

Fragment mass 3 m₃ = 0.3 kg moves up (y axis)

Moment before the break

X axis

     p₀ₓ = m v₀ₓ

Y Axis y

    p_{oy} = 0

After the break

X axis

   p_{fx} = m₂ v₂

Axis y

     p_{fy} = m₁ v₁ + m₃ v₃

Let's write the conservation of the moment and calculate

Y Axis  

     0 = m₁ v₁ + m₃ v₃

Let's clear the speed of fragment 3

     v₃ = - m₁ v₁ / m₃

     v₃ = - (-10) 1 / 0.3

     v₃ = 33.3 m / s

X axis

     M v₀ₓ = m₂ v₂

     v₂ = v₀ₓ M / m₂

     v₂ = 38.3  2 / 0.7

     v₂ = 109.4 m / s

The fragment speeds of 0.3 kg is 33.3 m / s on the y axis

                                         0.7 kg is 109.4 ms on the x axis

b) The speed of the fragment is 33.3 m / s and has a starting height of where the fragmentation occurred, let's calculate with kinematics

       v_{fy}² = v_{oy}² - 2 gy

       0 =  v_{oy}²-2gy

       y =  v_{oy}² / 2g

       y = 32.14² / 2 9.8

       y = 52.7 m

This is the height where the break occurs, which is the initial height for body movement of 0.3 kg

      v_{f}² =  v_{y}² - 2 g y₂

      0 =  v_{y}² - 2 g y₂

     y₂ =  v_{y}² / 2g

     y₂ = 33.3²/2 9.8

     y₂ = 56.58 m

Total body height is

      Y = y + y₂

      Y = 52.7 + 56.58

     Y = 109.3 m

8 0
3 years ago
The safest way to view an image of the sun is to use.
Nostrana [21]

Answer:

Pinhole Projection

Explanation:

You will get a great view if you project a sunlight coming thrugh a small hole onto a viewing card enclosed in a long box. The smaller the pinhole, the sharper the image

7 0
2 years ago
Other questions:
  • What are the activities involved in scientific method?
    9·1 answer
  • Which characteristic of the gas giants decreases with increasing distance from the sun?
    12·2 answers
  • Titin is a spring-shaped elastic protein that attaches to the thick filament and anchors it to the Z-discs of a sarcomere. If ti
    15·1 answer
  • A boulder rolls off a 100 meter cliff with a horizontal velocity of 2 m/s.
    7·1 answer
  • Liquid ammonia (boiling point = –33.4°C) can be used as a refrigerant and heat transfer fluid. How much energy is needed to heat
    9·1 answer
  • Which carries information by changing original sounds into numbers?
    11·2 answers
  • A car that increases its speed from 20km/h to 100km/h undergoes what acceleration
    5·1 answer
  • Which of the following features are found at an oceanic-continental convergent plate boundary?choose all that apply: 1-island ar
    11·2 answers
  • In short-track speed skating, the track has straight sections and semi-circles 16 m in diameter. Assume that a 66 kg skater goes
    15·1 answer
  • The square plates of a 3000-pF parallel-plate capacitor measure 40 mm by 40 mm and are separated by a dielectric that is 0.29 mm
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!