Answer:
(a) 348.4 m
(b) 256.7 m/s
(c) 127.2 m/s^2
Explanation:

(a) at t = 4 s
x = 2.3 x 4 + 5.3 x 4 x 4 x 4
x = 348.4 m
(b) The derivative of displacement function gives the value of instantaneous velocity.
So, v = dx / dt = 2.3 + 5.3 x 3 x t^2
v = 2.3 + 15.9 t^2
Put t = 4 s
So, v = 2.3 + 15.9 x 4 x 4
v = 256.7 m/s
(c) The derivative of velocity function with respect to time gives the value of instantaneous acceleration.
So, a = dv / dt = 5.3 x 3 x 2 x t
a = 31.8 t
Put t = 4 s
a = 31.8 x 4 = 127.2 m/s^2
Answer:
The center of mass move with the velocity of -3.487 m/s.
Explanation:
Given values of block A.
Mass of block A, (M1) = 4 kg
Speed of block A, (V1) = 2 m/s
Given values of block B.
Mass of block B, (M2) = 8.4 kg
Speed of block B, (V2) = -6.1 m/s
Below is the formula to find the velocity of center of mass.




Answer: P= W/t so P=50/20 =2.5 W
Transverse waves is what its called
The answer would be 70. I got my answer from www.iun.edu