Answer:
8.83m
Explanation:
Given parameters:
Acceleration = 7.8m/s²
Initial velocity = 0m/s
distance covered = 5m
Unknown:
Final velocity = ?
Solution:
The equation to solve this problem with is given as;
V² = U² + 2aS
V is the final velocity
U is the initial velocity
a is the acceleration
S is the distance
Input the parameters and solve;
V² = 0² + 2 x 7.8 x 5 = 78
V = √78 = 8.83m
Answer:
Radius of orbit = 3.992 ×
m
Altitude of Satellite =33541.9× m
Explanation:
Formula for gravitational force for a satellite of mass m moving in an orbit of radius r around a planet of mass M is given by;

Where G = Gravitational constant = 6.67408 × 10-11 
We are given
F= 800 N
m = 320 Kg
M = 5.972 ×
Kg
G = 6.67408 × 10-11 
We have to find radius r =?
putting values in formula;
==> 800 =6.67408 ×
× 320 × 5.972 ×
/ 
==> 800= 39.8576 ×
× 320 / 
==> 800 = 12754.43 ×
/ 
==>
= 12754.43 ×
/800
==>
=15.94 ×
==> r = 3.992 ×
m
==> r = 39920×
m
This is the distance of satellite from center of earth. To find altitude we need distance from surface of earth. So we will subtract radius of earth from this number to find altitude.
Radius of earth =6378.1 km = 6378.1 ×
m
Altitude = 39920×
- 6378.1 ×
Answer:
The angle that will have the most range (Goes further) <u>will be the one that is shot with 60 ° with the horizontal. </u>
Since the one that shoots with respect to the vertical, it will only reach higher. And it won't go as far as the horizontal.
Greetings.
Danna.
Answer:
extream heat and pressre split apart
Hello
1) The total distance the light has to cover to go from Earth to the Moon and back is twice the distance between the Earth and the Moon:

2) Given the relationship

where

is the speed of light, S the total distance covered calculate at point 1), and t the time, we can find the time the light needs to go from Earth to the Moon and back again: