All categories

3 years ago

When doing medical research with human subjects, which four limitations are unavoidable?

Chemistry

1 answer:

Fofino [41]3 years ago

8 0

Answer:

Answer

The limitations are-

1. Privacy of the individuals involved in the research process.

2. Physical and psychological risks should be minimized

3. The subjects should be chosen equitably

4. Only reasonable exposure to risks is admissible.

Explanation

The privacy of the individuals involved in the research must be taken into consideration. This will ensure safety of patient data and information. The risk of physical and physiological well being of the person must be taken into consideration in such a research. In addition to that, the subject must be made to understand every procedure and the risks involved before testing. Moreover, only minimal exposure to risks is allowed and must have been previously tested in animals to avoid deaths.

You might be interested in

Element x decays radioactively with a half life of 13 minutes. If there are 970 grams of element x, how long, to the nearest ten

Masteriza [31]

The time taken to the nearest tenth of a minute, would it take the element to decay to 98 grams is 9.897.

Half-life is the time half-time of the total decay of any element.

Given that, Initial amount = 970 grams

Final amount = 98 grams

Half life = 13 minutes

To find the half life

$Half life \times \dfrac{\dfrac{initial \;amount}{final\;amount} }{log2} \\\\\\13 \times \dfrac{\dfrac{970 }{98} }{log2} = 9.897$

Thus, the time taken to the nearest tenth of a minute, would it take the element to decay to 98 grams is 9.897.

Learn more about half-life

brainly.com/question/24710827

#SPJ4

5 0

2 years ago

Which common characteristics makes both batteries and fuel cells practical to use?

maks197457 [2]

Both the batteries and fuel cells are portable resources, which transforms the chemical energy into electrical energy.

A battery will produce electricity from the energy it has accumulated inside the battery, while a fuel cell produces the electricity from the fuel in an external fuel tank. This signifies that while a battery may run dead, a fuel cell will produce electricity as long as there is a supply of fuel.

3 0

3 years ago

Read 2 more answers

For the reaction Ti(s)+2F2(g)→TiF4(s) compute the theoretical yield of the product (in grams) for each of the following initial

Ostrovityanka [42]

Answer:

The answer to your question is 8.2 g of TiF₄

Explanation:

Data

Theoretical yield = ?

mass of Ti = 5 g

mass of F₂ = 5 g

Balanced chemical reaction

Ti(s) + 2F₂ (g) ⇒ TiF₄(g)

Process

1.- Calculate the Molar mass of reactants and products

Ti = 48 g

2F₂ = 2( 19 x 2) = 76 g

TiF₄ = 48 + 76 = 124 g

2.- Calculate the limiting reactant

theoretical proportion Ti/F₂ = 48/76 = 0.63

experimental proportion Ti/F₂ = 5/5 = 1

Conclusion The limiting reactant is F₂ because the experimental proportion was lower than the theoretical proportion.

3.- Calculate the theoretical yield using the mass of F₂

76 g of F₂ --------------- 124 g of TiF₄

5 g of F₂ --------------- x

x = (5 x 124) / 76

x = 8.15 g of TiF₄

4 0

3 years ago

Determine the composition of each phase in a cu-40% ni alloy at 1300c,

Morgarella [4.7K]

To be able to answer this, you need to have a phase diagram of Cu-Ni alloy. Create a vertical line along 40% in the x-axis. Then, create a horizontal line along the temperature at 1,300°C. The intersection lies outside of the α-L boundary. <em>Therefore, the system consist solely of the L-phase: 100% L.</em>

4 0

3 years ago

Find the mass of 3.00 mol of acetic acid, C2H4O2

Alinara [238K]

Molar mass acetic acid:

C₂H₄O₂ = 12 * 2 + 1 * 4 + 16 * 2 = 60.

n = mass / molar mass

3.00 = m / 60.0

m = 3.00 * 60.0

m = 180 g of <span>C₂H₄O₂

hope this helps!</span>

4 0

3 years ago